3. Eliminate c, and c, from Eq.(3b) by using Eq.(2). You should get the following: ö + ißå, + a°cq = 0 (4) 4. Solve this ODE (Hint: assume c, = e*). Then you should get the following general solution, c = e-i/2(Act + Be-«t) (5) where A and B are integration constant, and 2 = Va² + (3/2)² . 5. Based on the initial state, what is ca(0)? Show that this value leads to B = -A in Eq.(5). %3D
Percentage
A percentage is a number indicated as a fraction of 100. It is a dimensionless number often expressed using the symbol %.
Algebraic Expressions
In mathematics, an algebraic expression consists of constant(s), variable(s), and mathematical operators. It is made up of terms.
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Numbers are some measures used for counting. They can be compared one with another to know its position in the number line and determine which one is greater or lesser than the other.
Subtraction
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Please do 4, 5, and 6
![Exercise # 8
In class we introduced Rabi's model, a two level system with a time-dependent perturbation
Ha = H, = 0 and H = (H)* = aheut
where a and w are real parameters. This leads to the dynamical equation
aħe'(w-ww)t]
ih-
(1)
=
where wo
(Es – Ea)/h is a positive constant provided Ea < Eg. Then the state vector is
written in terms of the solutions, Ca(t) and c(t), as
|V(t)) = ca(t) e¯iEat/h|Ea) + c»(t) e¯-iEst/h|EL).
In what follows, you solve Eq. (1) for the initial state
|V(0)) = |Ea).
1. Let 3 = w - wo and write down Eq.(1) in components. You should get
Ca = -iaest
(2a)
Cb
C = -iae-ißt
(2b)
Ca
2. Take the time derivative of the above. You get two coupled second-order equations,
č, = aet (Bc, – ić,)
č, = -ae-ist (Bc, + ic,)
(За)
(3b)
3. Eliminate ca and ca from Eq.(3b) by using Eq.(2). You should get the following:
č, + ißc, + a²c, = 0
(4)
4. Solve this ODE (Hint: assume c, = et). Then you should get the following general
solution,
Cb = e-ißt/2(Aest + Be¬it)
(5)
where A and B are integration constant, and 2 = Va? + (B/2)2 .
5. Based on the initial state, what is c(0)? Show that this value leads to B = -A in
Еq (5).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa4426dc-92c3-4ac7-bd5a-9ba1dd10b9af%2F39ef7708-ded0-4154-b653-f292d26e7e03%2F69908tl_processed.png&w=3840&q=75)
![6. Show that Eq.(5) can now be written as
C, = 2iAe-ist/2 sin t
(6)
7. Differentiate Eq.(6) and then plug that into Eq.-(2) to find ca. You should get
2A
Ca =
- sin Qt + N cos Nt
(7)
8. Based on the initial state, what is c,(0)? Use this value to find A in Eq.(7).
9. Now put all the pieces of information together to show that the solution of Rabi's
model is
w - wo
Ca(t) = e"(w-ww)t/2
sin Nt
(8a)
cos Nt - i
2Ω
C(t) = e-i(w-wo)t/2
(8b)
sin Nt
where
w - wo
N = 1a2 +
(9)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa4426dc-92c3-4ac7-bd5a-9ba1dd10b9af%2F39ef7708-ded0-4154-b653-f292d26e7e03%2Fpg3r0cu_processed.png&w=3840&q=75)
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