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3. Determine the support reactions on the member shown below. The collar at B is fixed to the member and can slide vertically along the vertical shaft. The roller at A rests on a flat surface. The 100lb external force acts at the top of the member which has a total thickness of 0.5 ft P₁. 2 ft A 1.7 000 30° 10016 2 4 Ift 30 3 ft 05B Sin30= x= 21 si

3. Determine the support reactions on the member shown below. The collar at B is fixed to the member and can slide vertically along the vertical shaft. The roller at A rests on a flat surface. The 100lb external force acts at the top of the member which has a total thickness of 0.5 ft P₁. 2 ft A 1.7 000 30° 10016 2 4 Ift 30 3 ft 05B Sin30= x= 21 si

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Problem Statement:** Determine the support reactions on the member shown below. The collar at \( B \) is fixed to the member and can slide vertically along the vertical shaft. The roller at \( A \) rests on a flat surface. The 100 lb external force acts at the top of the member, which has a total thickness of 0.5 ft. **Diagram Explanation:** - The diagram displays a rigid member supported at two points: \( A \) and \( B \). - Point \( A \) has a roller support, allowing horizontal movement. - Point \( B \) has a collar, allowing vertical movement along the shaft. **Member Dimensions and Forces:** - The member is subjected to a 100 lb external force at an angle of 30° from the horizontal axis. - The length of the horizontal segment from the force application point to \( B \) is 3 ft. - The vertical segment from the horizontal segment to \( A \) is 1 ft. - From \( B \) to the ground is marked as 0.5 ft. **Trigonometric Details:** - A triangular force component breakdown is included: - \( \sin 30° = \frac{1}{2} \) - \( \cos 30° \) and component calculations are referenced with force direction. This setup suggests calculating the reaction forces at \( A \) and \( B \) using equilibrium equations for the static system.
Transcribed Image Text:**Problem Statement:** Determine the support reactions on the member shown below. The collar at \( B \) is fixed to the member and can slide vertically along the vertical shaft. The roller at \( A \) rests on a flat surface. The 100 lb external force acts at the top of the member, which has a total thickness of 0.5 ft. **Diagram Explanation:** - The diagram displays a rigid member supported at two points: \( A \) and \( B \). - Point \( A \) has a roller support, allowing horizontal movement. - Point \( B \) has a collar, allowing vertical movement along the shaft. **Member Dimensions and Forces:** - The member is subjected to a 100 lb external force at an angle of 30° from the horizontal axis. - The length of the horizontal segment from the force application point to \( B \) is 3 ft. - The vertical segment from the horizontal segment to \( A \) is 1 ft. - From \( B \) to the ground is marked as 0.5 ft. **Trigonometric Details:** - A triangular force component breakdown is included: - \( \sin 30° = \frac{1}{2} \) - \( \cos 30° \) and component calculations are referenced with force direction. This setup suggests calculating the reaction forces at \( A \) and \( B \) using equilibrium equations for the static system.
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