3. DETAILS HARMATHAP12 10.3.004. Find the absolute maxima and minima for f(x) on the interval [a, f(x) = x³ - 3x2 - 24x + 3, [-3, 6] absolute minimum (х, у) absolute maximum (x, y) = I |I|

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
3.
DETAILS
HARMATHAP12 10.3.004.
Find the absolute maxima and minima for f(x) on the interval [a, b].
f(x) = x3 - 3x2 - 24x + 3, [-3, 6]
absolute minimum
(х, у)
=
absolute maximum
(х, у)
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4.
DETAILS
HARMATHAP12 10.3.005.
Find the absolute maxima and minima for f(x) on the interval [a, b].
fx) - 2x3 - 3x2 - 36х - 6, [-1о, 10]
absolute minimum
(x, y)
absolute maximum
(х, у) -
Transcribed Image Text:3. DETAILS HARMATHAP12 10.3.004. Find the absolute maxima and minima for f(x) on the interval [a, b]. f(x) = x3 - 3x2 - 24x + 3, [-3, 6] absolute minimum (х, у) = absolute maximum (х, у) Need Help? Read It O Show My Work (Optional) e 4. DETAILS HARMATHAP12 10.3.005. Find the absolute maxima and minima for f(x) on the interval [a, b]. fx) - 2x3 - 3x2 - 36х - 6, [-1о, 10] absolute minimum (x, y) absolute maximum (х, у) -
1.
DETAILS
HARMATHAP12 10.3.001.
Find the absolute maxima and minima for f(x) on the interval [a, b].
f(x) = x3 - 2x2 – 4x + 3, [-1, 3]
absolute maximum
(х, у) 3D
(х, у) %3D
absolute minimum
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DETAILS
HARMATHAP12 10.3.003.
Find the absolute maxima and minima for f(x) on the interval [a, b].
f(x) = x3 + x2 - x + 2, [-3, 0]
absolute maximum
(х, у) %3D
absolute minimum
(х, у) 3D
2.
Transcribed Image Text:1. DETAILS HARMATHAP12 10.3.001. Find the absolute maxima and minima for f(x) on the interval [a, b]. f(x) = x3 - 2x2 – 4x + 3, [-1, 3] absolute maximum (х, у) 3D (х, у) %3D absolute minimum Need Help? Read It Watch It O Show My Work (Optional) O DETAILS HARMATHAP12 10.3.003. Find the absolute maxima and minima for f(x) on the interval [a, b]. f(x) = x3 + x2 - x + 2, [-3, 0] absolute maximum (х, у) %3D absolute minimum (х, у) 3D 2.
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