3. Design the flexural steel for a 5-inch thick simply-supported interior reinforced concrete one-way slab. The slab dimensions, dead and live loads, and concrete and steel properties are provided in the figures below. a. Compute the ultimate factored moment, Mu, for the slab. b. Compute the area of steel needed to resist tension in the section, As. Select a bar size and spacing to fit this requirement. ACI318-19 limitations on reinforcement spacing for one-way slabs are provided below. You may assume the minimum spacing is 1 inch. State all assumptions. 5 in. c. Compute a spacing required for the transverse reinforcement. The same limitations on reinforcement spacing apply as for part b. Is your design exhibit ductile behavior? Note that No. 3 bars have already been selected for this reinforcement. WD=15 b/ft² + slab weight WL= 30¹b/ft² span length 8 ft Normal Weight Concrete f'c = 4000 psi fy = 60000 psi Flexural steel 7.7.2 Reinforcement spacing 7.7.2.1 Minimum spacing s shall be in accordance with 25.2. 7.7.2.2 For nonprestressed and Class C prestressed slabs, spacing of bonded longitudinal reinforcement closest to the tension face shall not exceeds given in 24.3. span length 8 ft 7.7.2.3 For nonprestressed and Class T and C prestressed slabs with unbonded tendons, maximum spacing s of deformed longitudinal reinforcement shall be the lesser of 3h and 18 in. 7.7.2.4 Maximum spacing, s, of reinforcement required by 7.5.2.3 shall be the lesser of 5h and 18 in. No. 3 bars (temperature and shrinkage) d = 4 in.
3. Design the flexural steel for a 5-inch thick simply-supported interior reinforced concrete one-way slab. The slab dimensions, dead and live loads, and concrete and steel properties are provided in the figures below. a. Compute the ultimate factored moment, Mu, for the slab. b. Compute the area of steel needed to resist tension in the section, As. Select a bar size and spacing to fit this requirement. ACI318-19 limitations on reinforcement spacing for one-way slabs are provided below. You may assume the minimum spacing is 1 inch. State all assumptions. 5 in. c. Compute a spacing required for the transverse reinforcement. The same limitations on reinforcement spacing apply as for part b. Is your design exhibit ductile behavior? Note that No. 3 bars have already been selected for this reinforcement. WD=15 b/ft² + slab weight WL= 30¹b/ft² span length 8 ft Normal Weight Concrete f'c = 4000 psi fy = 60000 psi Flexural steel 7.7.2 Reinforcement spacing 7.7.2.1 Minimum spacing s shall be in accordance with 25.2. 7.7.2.2 For nonprestressed and Class C prestressed slabs, spacing of bonded longitudinal reinforcement closest to the tension face shall not exceeds given in 24.3. span length 8 ft 7.7.2.3 For nonprestressed and Class T and C prestressed slabs with unbonded tendons, maximum spacing s of deformed longitudinal reinforcement shall be the lesser of 3h and 18 in. 7.7.2.4 Maximum spacing, s, of reinforcement required by 7.5.2.3 shall be the lesser of 5h and 18 in. No. 3 bars (temperature and shrinkage) d = 4 in.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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This is civil engineering concrete design practice. Everything needed is provided. Please answer all parts to the best of your ability. Provide thorough answer and explanation. This is only one question with a max of 3 parts due to guidelines.
Transcribed Image Text:3. Design the flexural steel for a 5-inch thick simply-supported interior reinforced concrete one-way slab. The slab
dimensions, dead and live loads, and concrete and steel properties are provided in the figures below.
a. Compute the ultimate factored moment, Mu, for the slab.
b. Compute the area of steel needed to resist tension in the section, As. Select a bar size and spacing to fit
this requirement. ACI318-19 limitations on reinforcement spacing for one-way slabs are provided below.
You may assume the minimum spacing is 1 inch. State all assumptions.
5 in.
c. Compute a spacing required for the transverse reinforcement. The same limitations on reinforcement
spacing apply as for part b. Is your design exhibit ductile behavior? Note that No. 3 bars
have already been selected for this reinforcement.
WD=15 b/ft² + slab weight
WL= 30¹b/ft²
span length 8 ft
Normal Weight Concrete
f'c = 4000 psi
fy = 60000 psi
Flexural steel
7.7.2 Reinforcement spacing
7.7.2.1 Minimum spacing s shall be in accordance with 25.2.
7.7.2.2 For nonprestressed and Class C prestressed slabs,
spacing of bonded longitudinal reinforcement closest to the
tension face shall not exceed s given in 24.3.
span length 8 ft
7.7.2.3 For nonprestressed and Class T and C prestressed
slabs with unbonded tendons, maximum spacing s of
deformed longitudinal reinforcement shall be the lesser of
3h and 18 in.
7.7.2.4 Maximum spacing, s, of reinforcement required by
7.5.2.3 shall be the lesser of 5h and 18 in.
No. 3 bars (temperature and shrinkage)
d = 4 in.
Transcribed Image Text:TABLE A.2 Designations, Areas, Perimeters, and Weights of Standard Bars
U.S. Customary Units
Cross-Sectional Area (in.²)
Bar No.
3
4
5
6
7
8
9
10
11
14
18
Diameter (in.)
0.375
0.500
0.625
0.750
0.875
1.000
1.128
1.270
1.410
1.693
2.257
0.11
0.20
0.31
0.44
0.60
0.79
1.00
1.27
1.56
2.25
4.00
Unit Weight (lb/ft)
0.376
0.668
1.043
1.502
2.044
2.670
3.400
4.303
5.313
7.650
13.600
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