3. Consider the three domains D1, D2, and D3 shown below: Y-axis! D (0, 0) X-axis Domain D3 consists of all those points lying on the indicated straight line. What is the equation that that straight line? Assuming that maximum X and Y span of all the three domains are [-4, 4] and [4, -4], respectively, give the predicates and then give five sets of concrete values of test points for each of the domain Di Dr and D3, Find ON-points and OFF-points for each domain.

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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**Transcription of the Image for Educational Website**

---

**Question 3: Consider the three domains \( D_1, D_2, \) and \( D_3 \) shown below:**

The image contains a graph with a coordinate plane featuring three distinct regions labeled as domains \( D_1, D_2, \) and \( D_3 \):

- The graph is centered on a square with its corners at coordinates \((-4, 4), (4, 4), (4, -4), (-4, -4)\).
- The square is bisected by the X-axis and Y-axis, with the origin \((0, 0)\) at the center.
- Domain \( D_1 \) is located in the top left portion of the square.
- Domain \( D_2 \) is located in the bottom right portion of the square.
- Domain \( D_3 \) consists of a diagonal line crossing through the square, starting from \((-4, 0)\) and ending around \((4, 4)\).

**Task:**
Domain \( D_3 \) consists of all those points lying on the indicated straight line. What is the equation of that straight line? Assuming that the maximum \( X \) and \( Y \) span of all the three domains are \([-4, 4]\) and \([4, -4]\), respectively, give the predicates and then give five sets of concrete values of test points for each of the domains \( D_1, D_2, \) and \( D_3 \). Find ON-points and OFF-points for each domain.

---

**Graph Analysis:**

- **Axes:**
  - **X-axis**: Horizontal line running from \((-4, 0)\) to \((4, 0)\).
  - **Y-axis**: Vertical line running from \((0, 4)\) to \((0, -4)\).

- **Domains:**
  - **\( D_1 \):** Upper left section bounded by the negative half of the X-axis and positive half of the Y-axis.
  - **\( D_2 \):** Lower right section bounded by the positive half of the X-axis and negative half of the Y-axis.
  - **\( D_3 \):** Diagonal line is the primary feature here. It’s critical to determine its equation e
Transcribed Image Text:**Transcription of the Image for Educational Website** --- **Question 3: Consider the three domains \( D_1, D_2, \) and \( D_3 \) shown below:** The image contains a graph with a coordinate plane featuring three distinct regions labeled as domains \( D_1, D_2, \) and \( D_3 \): - The graph is centered on a square with its corners at coordinates \((-4, 4), (4, 4), (4, -4), (-4, -4)\). - The square is bisected by the X-axis and Y-axis, with the origin \((0, 0)\) at the center. - Domain \( D_1 \) is located in the top left portion of the square. - Domain \( D_2 \) is located in the bottom right portion of the square. - Domain \( D_3 \) consists of a diagonal line crossing through the square, starting from \((-4, 0)\) and ending around \((4, 4)\). **Task:** Domain \( D_3 \) consists of all those points lying on the indicated straight line. What is the equation of that straight line? Assuming that the maximum \( X \) and \( Y \) span of all the three domains are \([-4, 4]\) and \([4, -4]\), respectively, give the predicates and then give five sets of concrete values of test points for each of the domains \( D_1, D_2, \) and \( D_3 \). Find ON-points and OFF-points for each domain. --- **Graph Analysis:** - **Axes:** - **X-axis**: Horizontal line running from \((-4, 0)\) to \((4, 0)\). - **Y-axis**: Vertical line running from \((0, 4)\) to \((0, -4)\). - **Domains:** - **\( D_1 \):** Upper left section bounded by the negative half of the X-axis and positive half of the Y-axis. - **\( D_2 \):** Lower right section bounded by the positive half of the X-axis and negative half of the Y-axis. - **\( D_3 \):** Diagonal line is the primary feature here. It’s critical to determine its equation e
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