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- A cylindrical wire of radius 1.0 cm has charge distributed throughout its volume with a uniform charge density of (micro) 10.0 mC/m ³. The electric field at a point 0.50 cm from the surface of the wire is O 11 x 10 3 N/C. zero. O 7.6 x 10³ N/C. 3.8 x 10³ N/C.Three non-conducting infinite planes of charge lie in the xy plane. Let oi = 120.0 µC/m², 02 = -70.0 µC/m², 03 = m and z = 0.35 m respectively. a) Use Gauss' law to derive the equation for the electric field due to a non-conducting plane of charge. b) What is the magnitude and direction of the electric field at z = 0.50 m? c) If you place a proton at z = 0.50 m and release it from rest, what acceleration will the proton experience? 80.0 µC/m2, where plane 1 lies at z = 0.00 m, and plane 2 and 3 lie at z = 0.20 1.Q1) Assume that there are two spheres with diameters of 2 cm and 3.2 cm carry a uniform surface charge density of 4 mC/m^2 and -1.2 mC/m^2, respectively. a) What is the electric flux density at diameters of 3 cm and 5 cm? b) What is the surface charge density at diameter of 6 cm that makes the electric flux density equals zero at diameter of 7 cm?
- Find the direction of the electric field at point P. (The angle that the electric field makes with the positive x-axis.)Questions in the attachmentGiven a conducting semi-circle with radius r = 5 [cm] with a charge Q = -3 [C] uniformly distributed along conductor, what is the electric field at the center point (? y O A. O B. O C. O D. Q = -3 [NC] 6 5π² €0 5 cm 50m² € 0 [nC/cm²] i 3 [nC/cm²] j 3 50m² [nC/cm²] i 3 [nC/cm²] Ĵ 10T²0 X
- c) (a) Using Gauss's law calculate the electric field above a charged conductor. The system is shown in the figure below. Present the results in terms of surface charge density a. (1 E (b) A thin square (thicknesseclength), conducting plate 50 cm on a side lies in the xy plane. A total charge 4x10* C is placed on the plate. What is the electric field just below the plate? (1)07 A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and given by E. = [k (xy?) ↑ + k (x²y)j] N/C, where x,y are in meters, k =5.00 m3 1) Use ( E · îdA to calculate the flux through each surface. (should be SIX answers)R +Q +p Figure 3: r = Vx2 + y2 + z² 3. Sphere with electric charge +Q and infinite sphere at infinity with electric charge -Q. Consider a sphere of radius R field with electric charge of constant density p. (a) What is the units for the charge density p? (b) Express the total charge Q of the sphere in terms of this charge density. (c) Uses Gauss's Law to determine the electric field inside and outside the sphere. Express your answer in two forms: (i)in terms of total charge Q and (ii)in terms of charge density p. (d) Make a qualitative[but accurate] graph of the electric field from r = 0 to r = ∞. (e) Compute the potential relative to infinity V – V. at the following points (i) r =
- 9Determine the net charge inside a cube placed in a region with an electric field E = [6.00î + 7.00ĵ + ((2.80 m-¹)z + 4.00)Ê] N/C. Each side of the cube has a length L = 3.56 m. X What is the direction of the normal for each face of the cube? What is the flux through each face of the cube? Review Gauss's law. nCA solid insulating sphere of radius R has a volume charge density given by p = Po exp 4a3 where po, a > 0 are both constants and r is the distance from the centre of the insulator. Which of the following gives the correct expression for the electric field magnitude at a distance r