**Computer Chips and Surface Imperfections**Computer chips often contain surface imperfections. For a certain type of computer chips, the probability mass function of the number of defects $ X $ is presented in the following table:| $ x $ | 0 | 1 | 2 | 3 | 4 | 5 ||---------|-----|-----|-----|-----|-----|-----|| $ P(x) $ | 0.28 | 0.23 | 0.18 | 0.15 | 0.13 | 0.03 |**Tasks:**a) **Find $ P(X \leq 2) $.** *Compute the probability that the number of defects is 2 or less.*b) **Find $ P(X > 1) $.** *Compute the probability that the number of defects is greater than 1.*c) **Find the mean number of defects, $ \mu_x $.** *Calculate the expected value or average number of defects.*d) **Find the variance of the number of defects, $ \sigma^2 $.** *Calculate how much the number of defects varies from the mean number of defects.*

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Answered: 3. Computer chips often contain surface…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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The probability distribution of X, the number of imperfections for every 10 meters of a synthetic fabric in continuous rolls of uniform width, is given by 1 2 3 4 f(x) 0.41 0.37 0.17 0.05 0.01 find the mean and variance of X. (10 pts)
7. Assume that X and Y have a bivariate normal distribution having means 14.l and 1.3, and standard deviations 2.5 and 0.1, respectively, with correlation coefficient 0.8. Find P(Y >1.4|X =15) and P(X >15|Y = 1.4).
The dean of a university estimates that the mean number of classroom hours per week for full-time faculty is 11.0. As a member of the student council, you want to test this claim. A random sample of the number of classroom hours for eight full-time faculty for one week is shown in the table below. At a = 0.01, can you reject the dean's claim? Complete parts (a) through (d) below. Assume the population is normally distributed. 12.1 8.9 11.8 8.4 7.2 10.1 12.1 8.7
Let X,, X,, and x, represent the times necessary to perform three successive repair tasks at a certain service facility. Suppose they are independent, normal rv's with expected values 4,, Hz, and uz and variances o,2, 0,2, and o,2, respectively. (Round your answers to four decimal places.) A USE SALT 2 (a) If H1 = H2 = H3 = 60 and o,? = 0,2 . = 18, calculate P(T, s 204) and P(144 s T, s 204). P(T, s 204) = 0.9995 P(144 s T,s 204) = (b) Using the us and os given in part (a), calculate both P(54 s X) and P(58 s Xs 62). P(54 s X) P(58 s Xs 62) = 0.568 0.568 %3D (c) Using the u's and o's given in part (a), calculate P(-12 s X, - 0.5X2 - 0.5X3 s 6). P(-12 s X, - 0.5X, - 0.5x, s 6) = 0.8665
Calculate the missing values in the Stata output (SKIP E!!!). Two-sample t test with A variances X y combined diff Obs Ho: diff = 0 49 30 79 diff = mean(x) Ha: diff |t|) = Std. Dev. 6.5 7.4 6.935314 G E [95% Conf. Intervall 40.33298 39.62126 C F degrees of freedom = 44.86702 Pr{T > t) 42.72811 1.6996 77 Ha: diff > 0 H
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34) If a population exhibits a skew of -5.00 and an excess kurtosis of 5.00 which of the following is true? The population mean exceeds the median. The population variance exceeds the standard deviation. The population standard deviation exceeds the variance. The population median equals the mean. The population median exceeds the mean.
A manufacturing company produces bearings. One line of bearings is specified to be 1.64 centimeters (cm) in diameter. A major customer requires that the variance of the bearings be no more than .001 cm². The producer is required to test the bearings before they are shipped, and so the diameters of 16 bearings are measured with a precise instrument, resulting in the following values. Assume bearing diameters are normally distributed. Use the data and a = 0.01 to test to determine whether the population of these bearings is to be rejected because of too high a variance. 1.68 1.62 1.63 1.70 1.66 1.63 1.65 1.71 1.64 1.69 1.57 1.64 1.59 1.66 1.63 1.65 Appendix A Statistical Tables (Round your answer to 2 decimal places, e.g. 15.25.) The value of the test statistic is and we reject the null hypothesis ⇒
Let X have beta distribution with a = 2 and B = 3. Then the mean and the variance of X, respectively, are Select one: O a. 0.04 and 0.4 O b. 0.02 and 0.04 O c. 0.4 and 0.04 O d. 0.4 and 0.20
A magazine claims that the mean amount spent by a customer at Burger Stop is greater than the mean amount spent by a customer at Fry World. The results for samples of customer transactions for the two fast food restaurants are shown below. At x = 0.01, can you support the magazine's claim? Assume the population variances are equal. Assume the samples are random and independent, and the populations are normally distributed. Complete parts (a) through (e) below. Burger Stop Fry World X₁ = $11.22 X₂ = $10.59 $₁ = $0.79 $2 = $0.64 n₂ = 10 n₁ = 12 (a) Identify the claim and state Ho and H₂. Which is the correct claim below? O A. "The mean amount spent by a customer at Burger Stop is greater than the mean amount spent by a customer at Fry World." OB. "The mean amount spent by a customer at Burger Stop is equal to the mean amount spent by a customer at Fry World." O c. "The mean amount spent by a customer at Burger Stop is not equal to the mean amount spent by a customer at Fry World." O D.…
A random sample of size 10 yielded roughly "mound-shaped" data with a sample mean of 63.5 and a sample variance of 60.8. Let (L, OU) be the interval estimate that contains the population mean with 95% probability. Find the width of the interval. That is, find 0 – 0₁. 4.52 5.49 5.58 5.70 9.04 10.99 11.16 11.40 none of the other answers give the correct width

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