3. Compute the resultant of the three forces acting on the plate shown. Locate the intersectionwith AB and AC. Ans. R = 776 lb, x = 4 in, y = 3.43 in632 b1000 Ib722 lb6. The bricks on top of the beam and the supports at the bottom create the distributed loadingshown in the figure. Determine the required intensity "w" and dimension "d" of the right supportso that the resultant force and moment about point A of the system are both zero.Ans. W - 175 N/ m, d = 1.5 m05m200 N/m75 N/m0.5 m-3m

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Answered: 3. Compute the resultant of the three…

3. Compute the resultant of the three forces acting on the plate shown. Locate the intersection with AB and AC. Ans. R = 776 lb, x = 4 in, y = 3.43 in 632 lb 1000 Ib 1hJ 2כר 2"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

3. Compute the resultant of the three forces acting on the plate shown. Locate the intersection
with AB and AC. Ans. R = 776 lb, x = 4 in, y = 3.43 in
632 b
1000 Ib
722 lb
6. The bricks on top of the beam and the supports at the bottom create the distributed loading
shown in the figure. Determine the required intensity "w" and dimension "d" of the right support
so that the resultant force and moment about point A of the system are both zero.
Ans. W - 175 N/ m, d = 1.5 m
05m
200 N/m
75 N/m
0.5 m
-3m

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