NOTE: USE CANCELLATION OF UNITSPICTURE 2 REFERENCE FOR CONVERSION OF UNITS LENGTH1 m1 ft1 in1 yd=1 statute mile =PRESSURE1 atm=1 nautical mile =1 furlong=1 bar=POWER1 HP==|| || || || || || ||====|| || || || || || ||1 pferdestarke =1 TOR==3.2808 ft12 in2.54 cm3 ft5280 ft1.609 km6080 ft660 ft101325 Pa14.7 psi760 mm.Hg760 torr29.92 in.Hg1.0332 kg/cm²100 kPa746 watts33,000 ft-lbf/min550 ft-lbf/s2545 BTU/hr736 watts12,000 BTU/hr3.5167 kWAREA AND VOLUME=1 hectare1 acre1 ft³1 m³1 gal1 drumFORCE1 N1 dyne.1 lbf1 kgf=======10,000 m²43,560 ft²7.48 gal1000 L3.785 L4 quartz8 pints55 gal1 kg m/s²1x105 dynes1 gcm/s²32.174 lbm ft/s²4.448 N9.8066 NMASS1 kg1 lbm11 slug1 metric tonor (long ton)1 english ton =or (short ton)ENERGY1 BTU1 cal1J1 erg1 CHU=8m-cmdyne-s²|| || || || || || || ||=PROPORTIONALITY CONSTANTS, kkgm-mkN-s²2.2046 lbm16 oz7000 grains32.174 lbm1000 kg2000 lbm10001055 J778 ft-lbf252 cal4.187 J1 N-m1x107 erg1 dyne-cm.1.8 BTU Directions: Show your complete solutions clearly. Show proper unitconversions and cancellations. Do not use shift solve. Avoid erasures.Round off your answers to 4 decimal places.3.Compute the friction head loss in meters of a fluid at a certaincondition (S.G.-1.101) that is flowing at a rate of 130 lbm/minthrough a 5 cm, 50 m long pipe. The viscosity of the fluid is0.015x10-3 reyn.

Answered: Image /qna-images/answer/9473d01c-b62e-456d-b977-3d100e13e705.jpg

3. Compute the friction head loss in meters of a fluid at a certain condition (S.G.-1.101) that is flowing at a rate of 130 lbm/min through a 5 cm, 50 m long pipe. The viscosity of the fluid is 0.015x10-3 reyn.

3. Compute the friction head loss in meters of a fluid at a certain condition (S.G.-1.101) that is flowing at a rate of 130 lbm/min through a 5 cm, 50 m long pipe. The viscosity of the fluid is 0.015x10-3 reyn.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.

Question

NOTE: USE CANCELLATION OF UNITS

PICTURE 2 REFERENCE FOR CONVERSION OF UNITS

LENGTH
1 m
1 ft
1 in
1 yd
=
1 statute mile =
PRESSURE
1 atm
=
1 nautical mile =
1 furlong
=
1 bar
=
POWER
1 HP
=
=
|| || || || || || ||
=
=
=
=
|| || || || || || ||
1 pferdestarke =
1 TOR
=
=
3.2808 ft
12 in
2.54 cm
3 ft
5280 ft
1.609 km
6080 ft
660 ft
101325 Pa
14.7 psi
760 mm.Hg
760 torr
29.92 in.Hg
1.0332 kg/cm²
100 kPa
746 watts
33,000 ft-lbf/min
550 ft-lbf/s
2545 BTU/hr
736 watts
12,000 BTU/hr
3.5167 kW
AREA AND VOLUME
=
1 hectare
1 acre
1 ft³
1 m³
1 gal
1 drum
FORCE
1 N
1 dyne.
1 lbf
1 kgf
=
=
=
=
=
=
=
10,000 m²
43,560 ft²
7.48 gal
1000 L
3.785 L
4 quartz
8 pints
55 gal
1 kg m/s²
1x105 dynes
1 gcm/s²
32.174 lbm ft/s²
4.448 N
9.8066 N
MASS
1 kg
1 lbm
1
1 slug
1 metric ton
or (long ton)
1 english ton =
or (short ton)
ENERGY
1 BTU
1 cal
1J
1 erg
1 CHU
=
8m-cm
dyne-s²
|| || || || || || || ||
=
PROPORTIONALITY CONSTANTS, k
kgm-m
kN-s²
2.2046 lbm
16 oz
7000 grains
32.174 lbm
1000 kg
2000 lbm
1000
1055 J
778 ft-lbf
252 cal
4.187 J
1 N-m
1x107 erg
1 dyne-cm.
1.8 BTU

Directions: Show your complete solutions clearly. Show proper unit
conversions and cancellations. Do not use shift solve. Avoid erasures.
Round off your answers to 4 decimal places.
3.
Compute the friction head loss in meters of a fluid at a certain
condition (S.G.-1.101) that is flowing at a rate of 130 lbm/min
through a 5 cm, 50 m long pipe. The viscosity of the fluid is
0.015x10-3 reyn.

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