3. Complete the Frequency Distribution Table Class Interval Class Class fx Less Than Cumulative Frequency () Mark Frequency (< cmf) (x) 5-14 10 9.5 95 10 15-24 7 19.5 136.5 17 25-34 29.5 118 21 35-44 4. 39.5 158 25 45-54 3 49.5 148.5 28 55-64 65-74 59.5 28 69.5 139 30 N= 30 Efx= 795 4. Solve for the mean Solution: = susass. = 9.22 30 30 5. Identify the answers for a - e, then solve for the median. a. 15 Solution: b. LB = C. d.
3. Complete the Frequency Distribution Table Class Interval Class Class fx Less Than Cumulative Frequency () Mark Frequency (< cmf) (x) 5-14 10 9.5 95 10 15-24 7 19.5 136.5 17 25-34 29.5 118 21 35-44 4. 39.5 158 25 45-54 3 49.5 148.5 28 55-64 65-74 59.5 28 69.5 139 30 N= 30 Efx= 795 4. Solve for the mean Solution: = susass. = 9.22 30 30 5. Identify the answers for a - e, then solve for the median. a. 15 Solution: b. LB = C. d.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

Transcribed Image Text:3. Complete the Frequency Distribution Table
Class Interval
Class
Class
Less Than Cumulative
Frequency ()
Mark
Frequency (< cmf)
(x)
5-14
10
9.5
95
10
15-24
7
19.5
136.5
17
25-34
4
29.5
118
21
35-44
4
39.5
158
25
45-54
3
49.5
148.5
28
55-64
59.5
28
65-74
69.5
139
30
N= 30
Σx. 795
4.
olve for the mean
Solution: =.
2765
=9.22
30
30
5. Identify the answers for a-e, then solve for the median.
a.
-=
15
Solution:
b.
LB =
C.
i=
<efb=
fm =
d.
e.
6. Identify the answers for a- e, then solve for the mode
LB =
Solution:
b.
C.
fm
d.
fma =
e.
fmb =
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