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3. Check that each given function is the solution to the initial value problem. y(0) = 1, y'(0) = 2, y'(0) = 2, y(t) = -¹/2 (1+5t/2) (a) 4y" + 4y + y = 0,

3. Check that each given function is the solution to the initial value problem. y(0) = 1, y'(0) = 2, y'(0) = 2, y(t) = -¹/2 (1+5t/2) (a) 4y" + 4y + y = 0,

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Needed to be solved Q3 correctly in 30 minutes and get the thumbs up please show neat and clean work for it By hand solution needed
3.- Check that each given function is the solution to the initial value problem. y(0) = 1, = 2, y(t) = e-¹/2(1 + 5t/2) y'(0) = 2, y'(0) y(1)=-1, t>0, y'(1) = 4, (a) 4y" + 4y + y = 0, (b) 2t2y" + 3ty-y=0, (c) y" + y = sect, -π/2 <t</2, -π/2 <t</2, y(0)=y'(0) = 0, Determine of the form (+) - ort /TT! A factor anu- (a) y + 2y = 0 y(t) = 2t¹/2 - 3t-1 y(t) = (cost) (In cos t) + t sint the values of r for which each of the following differential equations has ODE, then its activa.
Transcribed Image Text:3.- Check that each given function is the solution to the initial value problem. y(0) = 1, = 2, y(t) = e-¹/2(1 + 5t/2) y'(0) = 2, y'(0) y(1)=-1, t>0, y'(1) = 4, (a) 4y" + 4y + y = 0, (b) 2t2y" + 3ty-y=0, (c) y" + y = sect, -π/2 <t</2, -π/2 <t</2, y(0)=y'(0) = 0, Determine of the form (+) - ort /TT! A factor anu- (a) y + 2y = 0 y(t) = 2t¹/2 - 3t-1 y(t) = (cost) (In cos t) + t sint the values of r for which each of the following differential equations has ODE, then its activa.
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