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3. Ca(OH)2 (aq) + H2SO4 (aq) + 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H2SO4 is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂O 1.839 g Ca(OH)2 x ? g H₂O 25.0 mL H₂SO4 x 1 mol Ca(OH)2 X 74.10 g Ca(OH)2 2 mol H₂O 1 mol Ca(OH)2 x 18.02 g H₂O = 0.8944 g H₂O 1 mol H₂O 1 L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 1000 mL H₂SO4 1 L H2SO4 1 mol H₂SO4 18.02 g H₂O = 0.180 g H₂O 1 mol H₂O ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O 25.0 mL H₂SO4 x 1 L H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 = 0.681 g CaSO4 1000 mL H₂SO4 1 L H₂SO4 1 mol H₂SO4 1 mol CaSO4 YOU MUST CALCULATE THE AMOUNT OF EXCESS REACTANT LEFT OVER AT THE END OF THE REACTION!!!!!!!

3. Ca(OH)2 (aq) + H2SO4 (aq) + 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H2SO4 is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂O 1.839 g Ca(OH)2 x ? g H₂O 25.0 mL H₂SO4 x 1 mol Ca(OH)2 X 74.10 g Ca(OH)2 2 mol H₂O 1 mol Ca(OH)2 x 18.02 g H₂O = 0.8944 g H₂O 1 mol H₂O 1 L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 1000 mL H₂SO4 1 L H2SO4 1 mol H₂SO4 18.02 g H₂O = 0.180 g H₂O 1 mol H₂O ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O 25.0 mL H₂SO4 x 1 L H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 = 0.681 g CaSO4 1000 mL H₂SO4 1 L H₂SO4 1 mol H₂SO4 1 mol CaSO4 YOU MUST CALCULATE THE AMOUNT OF EXCESS REACTANT LEFT OVER AT THE END OF THE REACTION!!!!!!!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the amount of excess reactant?

3. Ca(OH)2 (aq) + H2SO4 (aq) →+ 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H₂SO4 is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂O = 1.839 g Ca(OH)2 x 1 mol Ca(OH)2 X 74.10 g Ca(OH)2 ? g H₂O 25.0 mL H₂SO4 x 2 mol H₂O x 18.02 g H₂O = 1 mol Ca(OH)2 1 mol H₂O 0.8944 g H₂O 1 L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 18.02 g H₂O 1000 mL H2SO4 1 L H2SO4 1 mol H2SO4 1 mol H₂O = 0.180 g H₂O ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O 25.0 mL H₂SO4 x 1 L H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 = 0.681 g CaSO4 1000 mL H2SO4 1 L H2SO4 1 mol H₂SO4 1 mol CaSO4 YOU MUST CALCULATE THE AMOUNT OF EXCESS REACTANT LEFT OVER AT THE END OF THE REACTION!!!!!!!
Transcribed Image Text:3. Ca(OH)2 (aq) + H2SO4 (aq) →+ 2 H₂O (1) + CaSO4 (aq) (This is LIMITING REACTANT: H₂SO4 is the Limiting Reactant) Reaction Type: Neutralization Grams of Product (List the Product and the Amount): 0.180 g H₂O and 0.681 g CaSO4 ? g H₂O = 1.839 g Ca(OH)2 x 1 mol Ca(OH)2 X 74.10 g Ca(OH)2 ? g H₂O 25.0 mL H₂SO4 x 2 mol H₂O x 18.02 g H₂O = 1 mol Ca(OH)2 1 mol H₂O 0.8944 g H₂O 1 L H₂SO4 x 0.200 mol H₂SO4 x 2 mol H₂O x 18.02 g H₂O 1000 mL H2SO4 1 L H2SO4 1 mol H2SO4 1 mol H₂O = 0.180 g H₂O ONLY USE THE Limiting Reactant TO DETERMINE THE AMOUNT OF THE REMAINING PRODUCT(S). ? g H₂O 25.0 mL H₂SO4 x 1 L H₂SO4 x 0.200 mol H₂SO4 x 1 mol CaSO4 x 136.14 g CaSO4 = 0.681 g CaSO4 1000 mL H2SO4 1 L H2SO4 1 mol H₂SO4 1 mol CaSO4 YOU MUST CALCULATE THE AMOUNT OF EXCESS REACTANT LEFT OVER AT THE END OF THE REACTION!!!!!!!
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