3. Calculate the theoretical weight force of the water (W) displaced by the metal cylinder at 1, 2, 3, 4, and 5cm. Wa = RavALag) where gy is the density of water (= 1.0 x10³ kg/m³) L, is the length of the cylinder submerged, and g is gravitational acceleration. Wa1 (L, 1cm) = _ W:3 (L. 3cm) = , Ws5 (L, 5cm) = W2 (L. 2cm) = . Ws4 (L. 4cm) = . Wubmerzed (Show one weight force calculation below. Be careful to convert to SI units.)
3. Calculate the theoretical weight force of the water (W) displaced by the metal cylinder at 1, 2, 3, 4, and 5cm. Wa = RavALag) where gy is the density of water (= 1.0 x10³ kg/m³) L, is the length of the cylinder submerged, and g is gravitational acceleration. Wa1 (L, 1cm) = _ W:3 (L. 3cm) = , Ws5 (L, 5cm) = W2 (L. 2cm) = . Ws4 (L. 4cm) = . Wubmerzed (Show one weight force calculation below. Be careful to convert to SI units.)
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1-please help with the highlighted question 3 (which depends on attached answers from part 2) for this buoyancy problem. Thank you!
Transcribed Image Text:2. Calculate the circular cross-sectional area (A) of your aluminum cylinder. (A = zR?)
_4.15*10^-4_m?
Diameter=2.3cm
R=2.3cm/2=1.15cm
R=1.15cm/100=0.0115m
A=n*R^2
A= n*(0.0115m)^2
A=0.000415|
3. Calculate the theoretical weight force of the water (W) displaced by the metal cylinder at
1, 2, 3, 4, and 5cm.
(Wa = RALag) where gy is the density of water (= 1.0 x103 kg/m³) L. is the length of the
cylinder submerged, and g is gravitational acceleration.
Ws1 (L. 1cm) =
Ws3 (L. 3cm) =
Ws5 (L. 5cm) =
Ws2 (Ls 2cm) =
W:4 (L. 4cm) =
Waubmerzed
%3D
(Show one weight force calculation below. Be careful to convert to SI units.)
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