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3. Calculate the entropy changes of system and surroundings for the case of freezing of supercooled liquid silver at 1073 K. The melting point of silver is 1234 K and the heat of fusion is Hf = 11.2 kJ/mol. C' = 30.5J / mol / Kand C;=21.2+ 8.55×10°T +1.5×10°T*J/mol / K. HINT: Assume that the same %3D function for cp=f(T) can be used for the liquid silver even below melting point.

3. Calculate the entropy changes of system and surroundings for the case of freezing of supercooled liquid silver at 1073 K. The melting point of silver is 1234 K and the heat of fusion is Hf = 11.2 kJ/mol. C' = 30.5J / mol / Kand C;=21.2+ 8.55×10°T +1.5×10°T*J/mol / K. HINT: Assume that the same %3D function for cp=f(T) can be used for the liquid silver even below melting point.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Problem 3: Entropy Changes in Supercooled Silver** Calculate the entropy changes of the system and surroundings for the case of freezing of supercooled liquid silver at 1073 K. The melting point of silver is 1234 K and the heat of fusion is \( H_f = 11.2 \, \text{kJ/mol} \). For the specific heat capacities, use: - \( C_p^l = 30.5 \, \text{J/mol/K} \) for liquid silver. - \( C_p^s = 21.2 + 8.55 \times 10^{-3} T + 1.5 \times 10^{5} T^{-2} \, \text{J/mol/K} \) for solid silver. **HINT:** Assume that the same function for \( c_p = f(T) \) can be used for the liquid silver even below the melting point.
Transcribed Image Text:**Problem 3: Entropy Changes in Supercooled Silver** Calculate the entropy changes of the system and surroundings for the case of freezing of supercooled liquid silver at 1073 K. The melting point of silver is 1234 K and the heat of fusion is \( H_f = 11.2 \, \text{kJ/mol} \). For the specific heat capacities, use: - \( C_p^l = 30.5 \, \text{J/mol/K} \) for liquid silver. - \( C_p^s = 21.2 + 8.55 \times 10^{-3} T + 1.5 \times 10^{5} T^{-2} \, \text{J/mol/K} \) for solid silver. **HINT:** Assume that the same function for \( c_p = f(T) \) can be used for the liquid silver even below the melting point.
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