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3. Calculate the enthalpy and entropy changes of iron in the FCC structure when it is brought, without phase transformation from a temperature of 1250 K and a pressure of I atm to 1600 K and 10,000 atm. The data at 1250 K are as follows: V = 7.31 cm/mol a = 0.63 x 10K-1,B = 1.10 x 10-atm-1 C = 5.80 + 1.98 x 10-T Cal/K mol %3D !! %3D

3. Calculate the enthalpy and entropy changes of iron in the FCC structure when it is brought, without phase transformation from a temperature of 1250 K and a pressure of I atm to 1600 K and 10,000 atm. The data at 1250 K are as follows: V = 7.31 cm/mol a = 0.63 x 10K-1,B = 1.10 x 10-atm-1 C = 5.80 + 1.98 x 10-T Cal/K mol %3D !! %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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3. Calculate the enthalpy and entropy changes of iron in the FCC structure when it is brought, without phase transformation from a temperature of 1250 K and a pressure of I atm to 1600 K and 10,000 atm. The data at 1250 K are as follows: v = 7.31 cm/mol a = 0.63 x 10-4K-1,B = 1.10 x 10-6atm-1 C = 5.80 + 1.98 x 10-T Cal/K mol %3D !3!
Transcribed Image Text:3. Calculate the enthalpy and entropy changes of iron in the FCC structure when it is brought, without phase transformation from a temperature of 1250 K and a pressure of I atm to 1600 K and 10,000 atm. The data at 1250 K are as follows: v = 7.31 cm/mol a = 0.63 x 10-4K-1,B = 1.10 x 10-6atm-1 C = 5.80 + 1.98 x 10-T Cal/K mol %3D !3!
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