**Problem Statement**Bob Baffert has two thoroughbred horses in his barn that he brings out every morning to train for the upcoming races. Hoppertunity is a horse training for a 2,400-meter race and Dortmund is a horse training for an 1,800-meter race. In a given workout, Hoppertunity and Dortmund start running at the same time. Dortmund runs twice as fast as Hoppertunity; however, Hoppertunity starts 200 meters ahead of Dortmund. After 12.5 seconds, Dortmund catches up with Hoppertunity.Let \( r \) represent Hoppertunity’s rate. Match expressions to the boxes and symbols to the circles to create an equation that can be used to find the rate at which Hoppertunity runs. Not all expressions and symbols will be used, and you may use an expression and/or symbol twice.**Diagram Explanation**The diagram includes a series of boxes and circles in a linear arrangement. The following expressions and symbols are listed on the left side: - \( 2r \)- 12.5- 15- 200- 400- \( + \)- \( - \)- \( = \)These need to be matched appropriately to form an equation based on the described problem involving the horses' speeds and distances. The goal is to determine Hoppertunity's rate, \( r \), using the given conditions. ### Problem 4: Calculating Weekly SalesNina has been given the formula to figure out her weekly salary:\[ I = 0.88(9h + 0.12s) \]- **h** represents the number of hours Nina works per week.- **s** represents the monetary value of the sales Nina makes per week.**Objective:**Determine which of the following expressions represent the monetary value of the sales Nina makes in any given week. Select all that apply.**Options:**1. \[ s = 0.88l - 9h \]2. \[ s = \frac{l - 7.92h}{0.88} \]3. \[ s = \frac{l}{0.1056} - \frac{9h}{0.12} \]4. \[ s = \frac{l - 9h}{0.1056} \]5. \[ s = \frac{l - 7.92h}{0.1056} \]Evaluate each option to find which corresponds correctly to the given formula.

As per our guidelines, we are supposed to answer only one question (3 subparts) and the rest can be reposted 3.) Given: Let r be a Rate of Hoppertunity Rate of Dortmund =2r Let d be the distance Hoppertunity runs , then distance Dortmund runs is d+200m ∵ It took 12.5 seconds for Dortmund to catch Hoppertunity, it can be expressed as: d=12.5r for Hoppertunity d+200=12.5×2r for Dortmund---(1)By replacing d in the second equation, we get: 12.5r+200=12.5×2r 12.5r=200⇒r=20012.5 r=16m/sec substitute equation (1) d+200=12.5×2(16) d=(12.5×32)-200 =400-200 =200 Hoppertunity's rate r=16m/sec Dortmund's rate d=200m/sec The required answer is,