3. At T = 300K, 1bar of ¹60¹80 in a 1m³ box (lengths ax=ayaz = 1m) can be considered as an ideal gas. In that case, the average translational energy in each dimension for a molecule is given by: Ex = Ex = Ex = 1kT, where k = 1.38 × 10-23 J/K is the Boltzmann constant. The average rotational energy about an axis perpendicular to the O-O bond is: Erot=1kT, Evib = KT. and the average vibrational energy is: Given that the fundamental vibrational frequency for ¹60¹80 is w = 4.741 × 10¹³Hz, find the values of the quantum numbers nx, J, and u for an average ¹60¹80 molecule in this system.

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3.
At T = 300K, 1bar of ¹60¹80 in a 1m³ box (lengths ax ay = az = 1m) can be considered as
an ideal gas. In that case, the average translational energy in each dimension for a molecule is
given by:
Ex = Ex = Ex = 1kT,
where k = 1.38 x 10-23 J/K is the Boltzmann constant. The average rotational energy about an
axis perpendicular to the O=O bond is:
Erot=kT,
Evib = KT.
and the average vibrational energy is:
Given that the fundamental vibrational frequency for ¹60¹80 is w = 4.741 x 10¹³ Hz, find the
values of the quantum numbers nx, J, and u for an average ¹60¹80 molecule in this system.
Transcribed Image Text:3. At T = 300K, 1bar of ¹60¹80 in a 1m³ box (lengths ax ay = az = 1m) can be considered as an ideal gas. In that case, the average translational energy in each dimension for a molecule is given by: Ex = Ex = Ex = 1kT, where k = 1.38 x 10-23 J/K is the Boltzmann constant. The average rotational energy about an axis perpendicular to the O=O bond is: Erot=kT, Evib = KT. and the average vibrational energy is: Given that the fundamental vibrational frequency for ¹60¹80 is w = 4.741 x 10¹³ Hz, find the values of the quantum numbers nx, J, and u for an average ¹60¹80 molecule in this system.
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