3. An evaporator is concentrating solutions from the two different sources. The solution from the first source containing 20% NaCl and 15% NaOH, flows at the rate of 40 kg/min. The other solution containing 8% NaCl and 12% NaOH flows at the rate of 70 kg/min. The two streams are fed directly to the evaporator. In this process, 60% of the water evaporated. In order to obtain the desired concentration, 80% of NaOH and 65% of NaCl were recycled. However, 20% of H:0 was mixed on the recycle stream; to avoid this, purging of H20 must be done. If 30 % of the remaining water goes to the purge and the rest to the product, calculate the composition of NaOH and NaCl in the recycle stream and the product in the evaporator.
3. An evaporator is concentrating solutions from the two different sources. The solution from the first source containing 20% NaCl and 15% NaOH, flows at the rate of 40 kg/min. The other solution containing 8% NaCl and 12% NaOH flows at the rate of 70 kg/min. The two streams are fed directly to the evaporator. In this process, 60% of the water evaporated. In order to obtain the desired concentration, 80% of NaOH and 65% of NaCl were recycled. However, 20% of H:0 was mixed on the recycle stream; to avoid this, purging of H20 must be done. If 30 % of the remaining water goes to the purge and the rest to the product, calculate the composition of NaOH and NaCl in the recycle stream and the product in the evaporator.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:3. An evaporator is concentrating solutions from the two different sources. The solution from the first
source containing 20% NaCl and 15% NaOH, flows at the rate of 40 kg/min. The other solution
containing 8% NaCl and 12% NaOH flows at the rate of 70 kg/min. The two streams are fed
directly to the evaporator. In this process, 60% of the water evaporated. In order to obtain the
desired concentration, 80% of NaOH and 65% of NaCl were recycled. However, 20% of H:0 was
mixed on the recycle stream; to avoid this, purging of H20 must be done. If 30 % of the remaining
water goes to the purge and the rest to the product, calculate the composition of NaOH and NaCl in
the recycle stream and the product in the evaporator.
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