**Understanding the Motion of an Air Hockey Puck**3. **Scenario Analysis:** An air hockey puck is initially moving to the right on a horizontal air table, where friction is negligible. A force (\(\vec{F}_{\text{yp}}\)) is applied to the left, opposite to the puck's motion. This force is not necessarily constant and is used to stop the puck and then reverse its direction. **Diagram Explanation:** The diagram shows the puck on a horizontal surface with an arrow (\(\vec{F}_{\text{yp}}\)) pointing to the left. This arrow represents the applied force opposing the puck’s initial rightward movement. **Considerations:** By the end of the scenario, the puck travels to the left at a speed lower than its initial speed. If we consider the puck as the system, we need to determine whether the work done by the applied force is positive, negative, or zero. **Explanation:** Work done is calculated by the equation: \( W = \int \vec{F} \cdot d\vec{x} \). Here, the force applied is opposite to the initial direction of motion, which means the force does negative work while stopping the puck. Once the puck reverses direction, the work done in this phase is still negative as the force has reduced the puck's kinetic energy to less than its initial value. Thus, the work done by your force is negative.

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3. An air hockey puck is moving to the right along a horizontal air table (so friction is completely negligible). You apply a (not necessarily constant) force to the left that stops the puck and eventually turns the puck around. See the figure below. At the final time, the puck is now traveling to the left but with a speed less than the initial speed. If the puck is your system, is the work done by your force, positive, negative, or zero. Explain.

3. An air hockey puck is moving to the right along a horizontal air table (so friction is completely negligible). You apply a (not necessarily constant) force to the left that stops the puck and eventually turns the puck around. See the figure below. At the final time, the puck is now traveling to the left but with a speed less than the initial speed. If the puck is your system, is the work done by your force, positive, negative, or zero. Explain.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

**Understanding the Motion of an Air Hockey Puck**

3. **Scenario Analysis:**

An air hockey puck is initially moving to the right on a horizontal air table, where friction is negligible. A force (\(\vec{F}_{\text{yp}}\)) is applied to the left, opposite to the puck's motion. This force is not necessarily constant and is used to stop the puck and then reverse its direction.

**Diagram Explanation:**

The diagram shows the puck on a horizontal surface with an arrow (\(\vec{F}_{\text{yp}}\)) pointing to the left. This arrow represents the applied force opposing the puck’s initial rightward movement.

**Considerations:**

By the end of the scenario, the puck travels to the left at a speed lower than its initial speed. If we consider the puck as the system, we need to determine whether the work done by the applied force is positive, negative, or zero.

**Explanation:**

Work done is calculated by the equation: \( W = \int \vec{F} \cdot d\vec{x} \). Here, the force applied is opposite to the initial direction of motion, which means the force does negative work while stopping the puck. Once the puck reverses direction, the work done in this phase is still negative as the force has reduced the puck's kinetic energy to less than its initial value. Thus, the work done by your force is negative.

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