3. A W350x90 A36 steel section with a Fy = 248 MPa is used as a simply supported beam G(1) m long. The beam carries three equal concentrated loads at every quarter points. It also carries a uniform distributed load of L(2) kN/m (including its own weight). The allowable bending stress is 0.66F and allowable shear stress is 0.40Fy. Properties of W350x90: Flange width, br = 250 mm Flange thickness, tr = 16.40 mm Overall depth, d = 350 mm Web thickness, tw = 9.50 mm flange Moment of Inertia, I, = 266x 10° mm* Moment of Inertia, Iy = 44.54x10° mm“ Area, A = 11550 mm? web a. Determine the maximum value of each concentrated load based on flexure. b. Determine the maximum value of each concentrated load based on W Section shear.
3. A W350x90 A36 steel section with a Fy = 248 MPa is used as a simply supported beam G(1) m long. The beam carries three equal concentrated loads at every quarter points. It also carries a uniform distributed load of L(2) kN/m (including its own weight). The allowable bending stress is 0.66F and allowable shear stress is 0.40Fy. Properties of W350x90: Flange width, br = 250 mm Flange thickness, tr = 16.40 mm Overall depth, d = 350 mm Web thickness, tw = 9.50 mm flange Moment of Inertia, I, = 266x 10° mm* Moment of Inertia, Iy = 44.54x10° mm“ Area, A = 11550 mm? web a. Determine the maximum value of each concentrated load based on flexure. b. Determine the maximum value of each concentrated load based on W Section shear.
Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN:9781337094740
Author:Segui, William T.
Publisher:Segui, William T.
Chapter5: Beams
Section: Chapter Questions
Problem 5.5.8P
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G=5
M=9
L=6
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