3. A variable rightward force acts on an object of mass m = 2 kg, initially traveling with speed vo = 20 m/s, as it moves from x = 0 m to x = 10 m, as seen below: F(x) Vo x = 10 m m x = 0 m 0 x (m) 2 4 6 8 10 After the x = 10 m location, the object falls off a ledge. What is the speed of the object after it has fallen a distance of 50 m? F (N) 20 15 10 10 5

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### Physics Problem - Variable Force and Motion

**Problem Statement:**

A variable rightward force acts on an object of mass \( m = 2 \) kg, initially traveling with a speed \( v_0 = 20 \) m/s, as it moves from \( x = 0 \) m to \( x = 10 \) m, as shown below:

[Diagram of Object and Force]

In the diagram above:
- The green block represents the object with mass \( m \), initially at \( x = 0 \) m.
- \( v_0 \) = 20 m/s is the initial speed of the object.
- \( F(x) \) represents the variable force acting on the object as it moves rightward.

**Graph of Force \( F(x) \):**

The force \( F(x) \) as a function of distance \( x \) (in meters) is shown on the graph below:

![Graph of Force \( F(x) \)]

- The horizontal axis represents the position \( x \) (in meters) from 0 to 10 meters.
- The vertical axis represents the force \( F \) (in newtons) ranging from 0 to 20 N. 
- The graph is piecewise linear, initially rising from 5 N at \( x = 0 \) m to 10 N at \( x = 4 \) m, and then increasing steadily to 15 N at \( x = 10 \) m.

**Question:**

After the \( x = 10 \) m location, the object falls off a ledge. What is the speed of the object after it has fallen a distance of 50 m?

**Solution Outline:**
1. **Calculate Work Done by the Variable Force:**
    - Integrate the force \( F(x) \) over the distance from \( x = 0 \) m to \( x = 10 \) m to find work done.
    - Use the work-energy theorem to find the speed at \( x = 10 \) m.

2. **Free-Fall Motion after \( x = 10 \) m:**
    - Use kinematic equations to determine the speed of the object after falling 50 m under gravity.

By following these steps, you will be able to solve for the final speed of the object after falling 50 meters.
Transcribed Image Text:### Physics Problem - Variable Force and Motion **Problem Statement:** A variable rightward force acts on an object of mass \( m = 2 \) kg, initially traveling with a speed \( v_0 = 20 \) m/s, as it moves from \( x = 0 \) m to \( x = 10 \) m, as shown below: [Diagram of Object and Force] In the diagram above: - The green block represents the object with mass \( m \), initially at \( x = 0 \) m. - \( v_0 \) = 20 m/s is the initial speed of the object. - \( F(x) \) represents the variable force acting on the object as it moves rightward. **Graph of Force \( F(x) \):** The force \( F(x) \) as a function of distance \( x \) (in meters) is shown on the graph below: ![Graph of Force \( F(x) \)] - The horizontal axis represents the position \( x \) (in meters) from 0 to 10 meters. - The vertical axis represents the force \( F \) (in newtons) ranging from 0 to 20 N. - The graph is piecewise linear, initially rising from 5 N at \( x = 0 \) m to 10 N at \( x = 4 \) m, and then increasing steadily to 15 N at \( x = 10 \) m. **Question:** After the \( x = 10 \) m location, the object falls off a ledge. What is the speed of the object after it has fallen a distance of 50 m? **Solution Outline:** 1. **Calculate Work Done by the Variable Force:** - Integrate the force \( F(x) \) over the distance from \( x = 0 \) m to \( x = 10 \) m to find work done. - Use the work-energy theorem to find the speed at \( x = 10 \) m. 2. **Free-Fall Motion after \( x = 10 \) m:** - Use kinematic equations to determine the speed of the object after falling 50 m under gravity. By following these steps, you will be able to solve for the final speed of the object after falling 50 meters.
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