3. A simple beam has a 15 foot span and a W18 x 50 section. Determine the maximum bending stress and average shear stress due to two concentrated loads of 5000 lbs. each applied at the third points of the span and an uniform load of 2000 lbs./ft (this includes the weight of the beam) over the entire length of the beam. (15pts) 2000 lbs/ft 5 5000 lbs 5 5000 lbs 5 R2

3. A simple beam has a 15 foot span and a W18 x 50 section. Determine the maximum bending stress and average shear stress due to two concentrated loads of 5000 lbs. each applied at the third points of the span and an uniform load of 2000 lbs./ft (this includes the weight of the beam) over the entire length of the beam. (15pts) 2000 lbs/ft 5 5000 lbs 5 5000 lbs 5 R2

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

I’m confused if I’m doing this right and where to go next

R1
3. A simple beam has a 15 foot span and a W18 x 50 section. Determine the maximum
bending stress and average shear stress due to two concentrated loads of 5000 lbs. each
applied at the third points of the span and an uniform load of 2000 lbs./ft (this includes
the weight of the beam) over the entire length of the beam. (15pts)
2000 lbs/ft
5
5000 lbs
EMA= -(5000x5)-(5000
R2= 20000
20,000-(2,000x (5+x))-5000=0
5
Fy= -(2000x15)-5000-5000 + 20000 + R.
R₁ = 20000
20,000-10,000-2,000x - 5,000=0
X=2.5ft
5000 lbs
x 10) - 12000 x 15 x 7.5) (R2 x 15)
5
R2

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