3. A researcher investigated the effects of cold on hypertension in rats by randomly assigning six rats to a 26°C environment and six to a 5°C environment and recording their blood pressures. Rat 2 3 4 5 9. 10 11 12 5 5 Temp (C) 26 26 26 26 26 26 5 5 5 Blood 152 149 176 157 182 179 369 354 423 366 375 384 Pressure (b) Regardless of your answer to part (a), run a t-test for the difference between the two treatment means at the a = 5% level of significance. Specifically, we are interested in knowing if there exists sufficient statistical evidence to support the claim that low temperatures increase blood pressure in rats. Be sure to state the null and alternative hypotheses, calculate the appropriate test statistic, calculate the p- value, and state your conclusions. The null hypothesis: Ho : H1 = H2 The alternative hypothesis: Ha : µ1 > µ2 data: bloodpressure26 and bloodpressure5 t = -18.509, df=8.3215, p-value = 2.348e-08 alternative hypothesis: true difference in means is less than 0 95 percent confidence interval: -Inf -191.4077 sample estimates: mean of x mean of y 165.8333 378.5000 Test statistic= -18.509 Right tailed p-value = (-18.5095, 8) = 0.9999999977 ????
3. A researcher investigated the effects of cold on hypertension in rats by randomly assigning six rats to a 26°C environment and six to a 5°C environment and recording their blood pressures. Rat 2 3 4 5 9. 10 11 12 5 5 Temp (C) 26 26 26 26 26 26 5 5 5 Blood 152 149 176 157 182 179 369 354 423 366 375 384 Pressure (b) Regardless of your answer to part (a), run a t-test for the difference between the two treatment means at the a = 5% level of significance. Specifically, we are interested in knowing if there exists sufficient statistical evidence to support the claim that low temperatures increase blood pressure in rats. Be sure to state the null and alternative hypotheses, calculate the appropriate test statistic, calculate the p- value, and state your conclusions. The null hypothesis: Ho : H1 = H2 The alternative hypothesis: Ha : µ1 > µ2 data: bloodpressure26 and bloodpressure5 t = -18.509, df=8.3215, p-value = 2.348e-08 alternative hypothesis: true difference in means is less than 0 95 percent confidence interval: -Inf -191.4077 sample estimates: mean of x mean of y 165.8333 378.5000 Test statistic= -18.509 Right tailed p-value = (-18.5095, 8) = 0.9999999977 ????
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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