3. A random variable that can be used to find a 0.954 confidence interval for u, the mean of the gamma distribution is (x-48) 5x = - 10-t(n-1) √48²/25 28
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- When X is a binomial random variable, the standard deviation of the probability distribution = the square root of npq If X is a binomial random variable, where there are 196 trials, and p = 0.252 find the standard deviation.X is a normally distributed random variable with a mean of 5 and a standard deviation of 2. For which value of a is P(X > a) = 0.6293? What is a?Suppose a random variable X has the following pdf. The random variable X has a Beta distribution with α = 3 and β = 2. Suppose we wanted to determine Var( 10X - 3 ). By the rules for variances, Var( 10X - 3 ) = * Var(X) + where, using the fact that X has a Beta distribution, Var(X) = Express answer as a decimal. Do not round.
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