3. A random sample of size nis selected from a population with mean 100 and standard deviation 20. Find the mean (µ,) and standard deviation (o, ) of the sample mean for each of the following values. а. n = 25 с. n = 64 b. п3D 36 d. n = 20 e. In which of these cases can we be assured that the sampling distribution of the sample mean will be approximately normally distributed?

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**Question 3: Sampling Distribution of the Sample Mean**

A random sample of size \( n \) is selected from a population with a mean of 100 and a standard deviation of 20. Find the mean (\(\mu_{\bar{x}}\)) and standard deviation (\(\sigma_{\bar{x}}\)) of the sample mean for each of the following values:

a. \( n = 25 \)

b. \( n = 36 \)

c. \( n = 64 \)

d. \( n = 20 \)

e. In which of these cases can we be assured that the sampling distribution of the sample mean will be approximately normally distributed?

**Explanation:**

For a sample size \( n \), the mean of the sampling distribution of the sample mean (\(\mu_{\bar{x}}\)) is equal to the mean of the population, which is 100. The standard deviation of the sampling distribution of the sample mean (\(\sigma_{\bar{x}}\)) is calculated using the formula:

\[
\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}
\]

where \(\sigma\) is the standard deviation of the population.

The Central Limit Theorem states that the sampling distribution of the sample mean will be approximately normally distributed if the sample size \( n \) is sufficiently large, typically \( n \geq 30 \).
Transcribed Image Text:**Question 3: Sampling Distribution of the Sample Mean** A random sample of size \( n \) is selected from a population with a mean of 100 and a standard deviation of 20. Find the mean (\(\mu_{\bar{x}}\)) and standard deviation (\(\sigma_{\bar{x}}\)) of the sample mean for each of the following values: a. \( n = 25 \) b. \( n = 36 \) c. \( n = 64 \) d. \( n = 20 \) e. In which of these cases can we be assured that the sampling distribution of the sample mean will be approximately normally distributed? **Explanation:** For a sample size \( n \), the mean of the sampling distribution of the sample mean (\(\mu_{\bar{x}}\)) is equal to the mean of the population, which is 100. The standard deviation of the sampling distribution of the sample mean (\(\sigma_{\bar{x}}\)) is calculated using the formula: \[ \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \] where \(\sigma\) is the standard deviation of the population. The Central Limit Theorem states that the sampling distribution of the sample mean will be approximately normally distributed if the sample size \( n \) is sufficiently large, typically \( n \geq 30 \).
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