Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
3. A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. 19 pounds was adult dog food and 18, pounds was puppy food. How many pounds of cat food did the pet store donate?

3. A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. 19 pounds was adult dog food and 18, pounds was puppy food. How many pounds of cat food did the pet store donate?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
See similar textbooks
icon
Related questions
Question
### Educational Exercise - Understanding and Solving Fractions **Problem 3:** A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. \(19 \frac{3}{4}\) pounds was adult dog food and \(18 \frac{7}{8}\) pounds was puppy food. How many pounds of cat food did the pet store donate? **Solution Approach:** 1. Convert each mixed number to an improper fraction or decimal. - \(19 \frac{3}{4} = \frac{79}{4}\) - \(18 \frac{7}{8} = \frac{151}{8}\) 2. Add the amounts of adult dog food and puppy food: - Convert to a common denominator or work with decimals. - If using decimals: - \(19 \frac{3}{4} = 19.75\) - \(18 \frac{7}{8} = 18.875\) - Sum = \(19.75 + 18.875 = 38.625\) 3. Subtract the sum from the total donation: - \(50 - 38.625 = 11.375\) 4. Convert the remaining amount back to a mixed number if necessary. Therefore, the pet store donated approximately \(11 \frac{3}{8}\) pounds of cat food. **Problem 4:** Thelma spent \(\frac{1}{6}\) of her weekly allowance on dog toys, \(\frac{1}{4}\) on a dog collar, and \(\frac{1}{3}\) on dog food. What fraction of her weekly allowance is left? **Solution Approach:** 1. Convert each fraction to have a common denominator, if necessary. In this case, a common denominator is 12. 2. Rewrite each fraction: - \(\frac{1}{6} = \frac{2}{12}\) - \(\frac{1}{4} = \frac{3}{12}\) - \(\frac{1}{3} = \frac{4}{12}\) 3. Sum the fractions: - \(\frac{2}{12} + \frac{3}{12} + \frac{4}{12} = \frac{9}{12} = \frac{3}{4}\) 4. Sub
Transcribed Image Text:### Educational Exercise - Understanding and Solving Fractions **Problem 3:** A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. \(19 \frac{3}{4}\) pounds was adult dog food and \(18 \frac{7}{8}\) pounds was puppy food. How many pounds of cat food did the pet store donate? **Solution Approach:** 1. Convert each mixed number to an improper fraction or decimal. - \(19 \frac{3}{4} = \frac{79}{4}\) - \(18 \frac{7}{8} = \frac{151}{8}\) 2. Add the amounts of adult dog food and puppy food: - Convert to a common denominator or work with decimals. - If using decimals: - \(19 \frac{3}{4} = 19.75\) - \(18 \frac{7}{8} = 18.875\) - Sum = \(19.75 + 18.875 = 38.625\) 3. Subtract the sum from the total donation: - \(50 - 38.625 = 11.375\) 4. Convert the remaining amount back to a mixed number if necessary. Therefore, the pet store donated approximately \(11 \frac{3}{8}\) pounds of cat food. **Problem 4:** Thelma spent \(\frac{1}{6}\) of her weekly allowance on dog toys, \(\frac{1}{4}\) on a dog collar, and \(\frac{1}{3}\) on dog food. What fraction of her weekly allowance is left? **Solution Approach:** 1. Convert each fraction to have a common denominator, if necessary. In this case, a common denominator is 12. 2. Rewrite each fraction: - \(\frac{1}{6} = \frac{2}{12}\) - \(\frac{1}{4} = \frac{3}{12}\) - \(\frac{1}{3} = \frac{4}{12}\) 3. Sum the fractions: - \(\frac{2}{12} + \frac{3}{12} + \frac{4}{12} = \frac{9}{12} = \frac{3}{4}\) 4. Sub
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,
SEE MORE TEXTBOOKS