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3. A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. 19 pounds was adult dog food and 18, pounds was puppy food. How many pounds of cat food did the pet store donate?

3. A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. 19 pounds was adult dog food and 18, pounds was puppy food. How many pounds of cat food did the pet store donate?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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### Educational Exercise - Understanding and Solving Fractions **Problem 3:** A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. \(19 \frac{3}{4}\) pounds was adult dog food and \(18 \frac{7}{8}\) pounds was puppy food. How many pounds of cat food did the pet store donate? **Solution Approach:** 1. Convert each mixed number to an improper fraction or decimal. - \(19 \frac{3}{4} = \frac{79}{4}\) - \(18 \frac{7}{8} = \frac{151}{8}\) 2. Add the amounts of adult dog food and puppy food: - Convert to a common denominator or work with decimals. - If using decimals: - \(19 \frac{3}{4} = 19.75\) - \(18 \frac{7}{8} = 18.875\) - Sum = \(19.75 + 18.875 = 38.625\) 3. Subtract the sum from the total donation: - \(50 - 38.625 = 11.375\) 4. Convert the remaining amount back to a mixed number if necessary. Therefore, the pet store donated approximately \(11 \frac{3}{8}\) pounds of cat food. **Problem 4:** Thelma spent \(\frac{1}{6}\) of her weekly allowance on dog toys, \(\frac{1}{4}\) on a dog collar, and \(\frac{1}{3}\) on dog food. What fraction of her weekly allowance is left? **Solution Approach:** 1. Convert each fraction to have a common denominator, if necessary. In this case, a common denominator is 12. 2. Rewrite each fraction: - \(\frac{1}{6} = \frac{2}{12}\) - \(\frac{1}{4} = \frac{3}{12}\) - \(\frac{1}{3} = \frac{4}{12}\) 3. Sum the fractions: - \(\frac{2}{12} + \frac{3}{12} + \frac{4}{12} = \frac{9}{12} = \frac{3}{4}\) 4. Sub
Transcribed Image Text:### Educational Exercise - Understanding and Solving Fractions **Problem 3:** A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. \(19 \frac{3}{4}\) pounds was adult dog food and \(18 \frac{7}{8}\) pounds was puppy food. How many pounds of cat food did the pet store donate? **Solution Approach:** 1. Convert each mixed number to an improper fraction or decimal. - \(19 \frac{3}{4} = \frac{79}{4}\) - \(18 \frac{7}{8} = \frac{151}{8}\) 2. Add the amounts of adult dog food and puppy food: - Convert to a common denominator or work with decimals. - If using decimals: - \(19 \frac{3}{4} = 19.75\) - \(18 \frac{7}{8} = 18.875\) - Sum = \(19.75 + 18.875 = 38.625\) 3. Subtract the sum from the total donation: - \(50 - 38.625 = 11.375\) 4. Convert the remaining amount back to a mixed number if necessary. Therefore, the pet store donated approximately \(11 \frac{3}{8}\) pounds of cat food. **Problem 4:** Thelma spent \(\frac{1}{6}\) of her weekly allowance on dog toys, \(\frac{1}{4}\) on a dog collar, and \(\frac{1}{3}\) on dog food. What fraction of her weekly allowance is left? **Solution Approach:** 1. Convert each fraction to have a common denominator, if necessary. In this case, a common denominator is 12. 2. Rewrite each fraction: - \(\frac{1}{6} = \frac{2}{12}\) - \(\frac{1}{4} = \frac{3}{12}\) - \(\frac{1}{3} = \frac{4}{12}\) 3. Sum the fractions: - \(\frac{2}{12} + \frac{3}{12} + \frac{4}{12} = \frac{9}{12} = \frac{3}{4}\) 4. Sub
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