3. (a) On most computers, the computation of Ja is based on Newton's method. - a = 0, and show that it can be Set up the Newton iteration for solving x2 written in the form 1 Xn + a Xn+1 = n > 0 Xn (b) Derive the error and relative error formulas 1 Va – Xn+1 2.xn vā ¿(*x – »^) ya Rel(xn)l´ 2xn Rel(xn+1) Hint: Apply (3.19). (c) For xo near Ja, the last formula becomes Rel(xp+1) - [Rel(x„)I², n > 0 - Assuming Rel(xo) = 0.1, use this formula to estimate the relative error in X1, X2, Xз, аnd x4.

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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On most computers, the computation of a is based on Newton's method.
Set up the Newton iteration for solving x2 - a =
3. (а)
0, and show that it can be
written in the form
1
a
Xn +
2
n > 0
Хn+1
Xn
(b) Derive the error and relative error formulas
1
Va - Xn+1 =
(Wa – xn)?
2.xn
Va Rel(xn)I²
2.xn
Rel(xn+1) = -
Нint: Apply (3.19).
(c)
For xo near va, the last formula becomes
Rel(xn+1) - -
1
[Rel(x,)°,
n > 0
2-
Assuming Rel (xo) = 0.1, use this formula to estimate the relative error in
X1, X2, Хз, аnd x4.
Transcribed Image Text:On most computers, the computation of a is based on Newton's method. Set up the Newton iteration for solving x2 - a = 3. (а) 0, and show that it can be written in the form 1 a Xn + 2 n > 0 Хn+1 Xn (b) Derive the error and relative error formulas 1 Va - Xn+1 = (Wa – xn)? 2.xn Va Rel(xn)I² 2.xn Rel(xn+1) = - Нint: Apply (3.19). (c) For xo near va, the last formula becomes Rel(xn+1) - - 1 [Rel(x,)°, n > 0 2- Assuming Rel (xo) = 0.1, use this formula to estimate the relative error in X1, X2, Хз, аnd x4.
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