3. A new genetic screening method is developed for early detection of cancer. To evaluate the test, 1000 people are randomly selected. A current and more precise technique determines that 6% of the 1000 people have a cancer. Now, each of the 1000 people are subjected to new genetic screening test and following results are recorded: Test (+) Test (-) Cancer 0.97 0.03 Healthy 0.04 0.96 a) Based on these results, what is the probability of a randomly chosen person having a cancer given that new genetic screening indicates the disease? Draw a tree diagram and place appropriate probabilities to each branch.

MATLAB: An Introduction with Applications
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3. A new genetic screening method is developed for early detection of cancer. To evaluate
the test, 1000 people are randomly selected. A current and more precise technique
determines that 6% of the 1000 people have a cancer. Now, each of the 1000 people are
subjected to new genetic screening test and following results are recorded:
Test (+)
Test (-)
Cancer
0.97
0.03
Healthy
0.04
0.96
a) Based on these results, what is the probability of a randomly chosen person having a
cancer given that new genetic screening indicates the disease? Draw a tree diagram and
place appropriate probabilities to each branch.
b) What is the probability that a person has a cancer after a second positive result?
P =
Transcribed Image Text:3. A new genetic screening method is developed for early detection of cancer. To evaluate the test, 1000 people are randomly selected. A current and more precise technique determines that 6% of the 1000 people have a cancer. Now, each of the 1000 people are subjected to new genetic screening test and following results are recorded: Test (+) Test (-) Cancer 0.97 0.03 Healthy 0.04 0.96 a) Based on these results, what is the probability of a randomly chosen person having a cancer given that new genetic screening indicates the disease? Draw a tree diagram and place appropriate probabilities to each branch. b) What is the probability that a person has a cancer after a second positive result? P =
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