3. A mass of 0.5 kg hangs from a spring of negligible mass. When an additional mass- of 0.2 kg is attached to the 0.5 kg, the spring is stretched an additional 4 cm. When the 0.2 kg mass is abruptly removed, the amplitude of the resultant vibrations of the 0.5 kg mass is observed to decrease to 1/e its original amplitude in 1 second. (Note: The force on a mass due to gravity = 9.8 x mass.) The resultant displacement is given by the equation: Thi x = A e ³t cos(@dt +ø) where at time t = 0, the decay in amplitude is assumed to be negligible and the displacement x is found to be 3.5cm. Calculate: a). The spring constant, S. b). The mechanical resistance, Rm - Nm- A ing is T= 2m c). The frequency of damped oscillation, @d. d). The phase constant, ø. Rm

Elements Of Electromagnetics
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Explain how they got d?
3. A mass of 0.5 kg hangs from a spring of negligible mass. When an additional mass-
of 0.2 kg is attached to the 0.5 kg, the spring is stretched an additional 4 cm.
When
When the 0.2 kg mass is abruptly removed, the amplitude of the resultant vibrations
of the 0.5 kg mass is observed to decrease to 1/e its original amplitude in 1 second.
(Note: The force on a mass due to gravity = 9.8 x mass.)
The resultant displacement is given by the equation:
x = A e ³t cos(@at +ø)
Thi
where at time t = 0, the decay in amplitude is assumed to be negligible and the
displacement x is found to be 3.5cm.
Calculate:
a). The spring constant, S.
b). The mechanical resistance, Rm
c). The frequency of damped oscillation, @d.
d). The phase constant, ø.
Nm-hals
is
T= 2m
Rm
Transcribed Image Text:3. A mass of 0.5 kg hangs from a spring of negligible mass. When an additional mass- of 0.2 kg is attached to the 0.5 kg, the spring is stretched an additional 4 cm. When When the 0.2 kg mass is abruptly removed, the amplitude of the resultant vibrations of the 0.5 kg mass is observed to decrease to 1/e its original amplitude in 1 second. (Note: The force on a mass due to gravity = 9.8 x mass.) The resultant displacement is given by the equation: x = A e ³t cos(@at +ø) Thi where at time t = 0, the decay in amplitude is assumed to be negligible and the displacement x is found to be 3.5cm. Calculate: a). The spring constant, S. b). The mechanical resistance, Rm c). The frequency of damped oscillation, @d. d). The phase constant, ø. Nm-hals is T= 2m Rm
d)
-Bb
At tão, Xo = è Acosø
A
but
So
"(
4 cm
at t=0,
At
has decayed minimally
Де
A
cos 0 =
13
3
*
?
* Tho is
bit strange
t
e-1t term will
е
still count from the
at
which
x=
know the amplit nah
,ie:
X.
A
J
3. Sem
}}
ده ) -
point
oscillations start
ارم = 8
|
0.035
0.04
29
Xo
A
Transcribed Image Text:d) -Bb At tão, Xo = è Acosø A but So "( 4 cm at t=0, At has decayed minimally Де A cos 0 = 13 3 * ? * Tho is bit strange t e-1t term will е still count from the at which x= know the amplit nah ,ie: X. A J 3. Sem }} ده ) - point oscillations start ارم = 8 | 0.035 0.04 29 Xo A
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