3. A mass of 0.5 kg hangs from a spring of negligible mass. When an additional mass- of 0.2 kg is attached to the 0.5 kg, the spring is stretched an additional 4 cm. When the 0.2 kg mass is abruptly removed, the amplitude of the resultant vibrations of the 0.5 kg mass is observed to decrease to 1/e its original amplitude in 1 second. (Note: The force on a mass due to gravity = 9.8 x mass.) The resultant displacement is given by the equation: Thi x = A e ³t cos(@dt +ø) where at time t = 0, the decay in amplitude is assumed to be negligible and the displacement x is found to be 3.5cm. Calculate: a). The spring constant, S. b). The mechanical resistance, Rm - Nm- A ing is T= 2m c). The frequency of damped oscillation, @d. d). The phase constant, ø. Rm
3. A mass of 0.5 kg hangs from a spring of negligible mass. When an additional mass- of 0.2 kg is attached to the 0.5 kg, the spring is stretched an additional 4 cm. When the 0.2 kg mass is abruptly removed, the amplitude of the resultant vibrations of the 0.5 kg mass is observed to decrease to 1/e its original amplitude in 1 second. (Note: The force on a mass due to gravity = 9.8 x mass.) The resultant displacement is given by the equation: Thi x = A e ³t cos(@dt +ø) where at time t = 0, the decay in amplitude is assumed to be negligible and the displacement x is found to be 3.5cm. Calculate: a). The spring constant, S. b). The mechanical resistance, Rm - Nm- A ing is T= 2m c). The frequency of damped oscillation, @d. d). The phase constant, ø. Rm
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Explain how they got d?

Transcribed Image Text:3. A mass of 0.5 kg hangs from a spring of negligible mass. When an additional mass-
of 0.2 kg is attached to the 0.5 kg, the spring is stretched an additional 4 cm.
When
When the 0.2 kg mass is abruptly removed, the amplitude of the resultant vibrations
of the 0.5 kg mass is observed to decrease to 1/e its original amplitude in 1 second.
(Note: The force on a mass due to gravity = 9.8 x mass.)
The resultant displacement is given by the equation:
x = A e ³t cos(@at +ø)
Thi
where at time t = 0, the decay in amplitude is assumed to be negligible and the
displacement x is found to be 3.5cm.
Calculate:
a). The spring constant, S.
b). The mechanical resistance, Rm
c). The frequency of damped oscillation, @d.
d). The phase constant, ø.
Nm-hals
is
T= 2m
Rm

Transcribed Image Text:d)
-Bb
At tão, Xo = è Acosø
A
but
So
"(
4 cm
at t=0,
At
has decayed minimally
Де
A
cos 0 =
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3
*
?
* Tho is
bit strange
t
e-1t term will
е
still count from the
at
which
x=
know the amplit nah
,ie:
X.
A
J
3. Sem
}}
ده ) -
point
oscillations start
ارم = 8
|
0.035
0.04
29
Xo
A
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