3. A mass m = 0.4 kg is attached to a vertical hanging spring, which obeys Hooke's Law. After hanging the weight the spring is stretched from its equilibrium position by Ayo released from rest. The period of this system is 0.1 m. The mass is then extended an additional Ay = 0.1 m upward and (a) T = 0.010s s or bluole sbiby (b) T = 0.063 s (c) T = 0.100 s (d) (d) T = 0.628 s

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(3)

**Problem Statement:**

A mass \( m = 0.4 \, \text{kg} \) is attached to a vertical hanging spring, which obeys Hooke's Law. After hanging the weight, the spring is stretched from its equilibrium position by \( \Delta y_0 = 0.1 \, \text{m} \). The mass is then extended an additional \( \Delta y = 0.1 \, \text{m} \) upward and released from rest. The period of this system is

**Options:**

(a) \( T = 0.010 \, \text{s} \)  
(b) \( T = 0.063 \, \text{s} \)  
(c) \( T = 0.100 \, \text{s} \)  
(d) \( T = 0.628 \, \text{s} \)  

---

**Explanation:**

The problem involves a vertical spring-mass system. The goal is to determine the period \( T \) of the oscillation of the mass attached to the spring. The period is the time it takes to complete one full oscillation. The system obeys Hooke's Law, which describes the force exerted by a spring as proportional to its displacement from the equilibrium position. The period of a mass-spring system can be calculated using the formula:

\[ T = 2\pi \sqrt{\frac{m}{k}} \]

where \( m \) is the mass and \( k \) is the spring constant. Here, \( m = 0.4 \, \text{kg} \). The problem requires understanding the relationship between the stretch of the spring and the properties of the oscillation to find the correct period from the given options.
Transcribed Image Text:**Problem Statement:** A mass \( m = 0.4 \, \text{kg} \) is attached to a vertical hanging spring, which obeys Hooke's Law. After hanging the weight, the spring is stretched from its equilibrium position by \( \Delta y_0 = 0.1 \, \text{m} \). The mass is then extended an additional \( \Delta y = 0.1 \, \text{m} \) upward and released from rest. The period of this system is **Options:** (a) \( T = 0.010 \, \text{s} \) (b) \( T = 0.063 \, \text{s} \) (c) \( T = 0.100 \, \text{s} \) (d) \( T = 0.628 \, \text{s} \) --- **Explanation:** The problem involves a vertical spring-mass system. The goal is to determine the period \( T \) of the oscillation of the mass attached to the spring. The period is the time it takes to complete one full oscillation. The system obeys Hooke's Law, which describes the force exerted by a spring as proportional to its displacement from the equilibrium position. The period of a mass-spring system can be calculated using the formula: \[ T = 2\pi \sqrt{\frac{m}{k}} \] where \( m \) is the mass and \( k \) is the spring constant. Here, \( m = 0.4 \, \text{kg} \). The problem requires understanding the relationship between the stretch of the spring and the properties of the oscillation to find the correct period from the given options.
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