3. A golf ball leaves a golf club with an initial velocity of 30 m/s at an angle of 50° with the horizontal. a. What is the vertical component of the golf ball's initial velocity? b. What is the total time flight time of the ball?
3. A golf ball leaves a golf club with an initial velocity of 30 m/s at an angle of 50° with the horizontal. a. What is the vertical component of the golf ball's initial velocity? b. What is the total time flight time of the ball?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Projectile Motion Problem**
A golf ball leaves a golf club with an initial velocity of 30 m/s at an angle of 50° with the horizontal.
**a. What is the vertical component of the golf ball's initial velocity?**
To find the vertical component (\(v_y\)) of the initial velocity, use the equation:
\[ v_y = v \cdot \sin(\theta) \]
where:
- \(v = 30 \, \text{m/s}\) (initial velocity)
- \(\theta = 50^\circ\) (angle with the horizontal)
**b. What is the total time flight time of the ball?**
The total time of flight can be found using the vertical component of the velocity and the acceleration due to gravity (\(g = 9.81 \, \text{m/s}^2\)).
The time to reach maximum height is given by:
\[ t_{\text{up}} = \frac{v_y}{g} \]
The total time of flight (\(T\)) is twice the time to reach maximum height:
\[ T = 2 \times t_{\text{up}} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a1de6f8-2a43-4fe6-832a-03652b3ee148%2F3dd848c0-94d9-4b76-a6e1-bada6d132340%2F188ugqh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Projectile Motion Problem**
A golf ball leaves a golf club with an initial velocity of 30 m/s at an angle of 50° with the horizontal.
**a. What is the vertical component of the golf ball's initial velocity?**
To find the vertical component (\(v_y\)) of the initial velocity, use the equation:
\[ v_y = v \cdot \sin(\theta) \]
where:
- \(v = 30 \, \text{m/s}\) (initial velocity)
- \(\theta = 50^\circ\) (angle with the horizontal)
**b. What is the total time flight time of the ball?**
The total time of flight can be found using the vertical component of the velocity and the acceleration due to gravity (\(g = 9.81 \, \text{m/s}^2\)).
The time to reach maximum height is given by:
\[ t_{\text{up}} = \frac{v_y}{g} \]
The total time of flight (\(T\)) is twice the time to reach maximum height:
\[ T = 2 \times t_{\text{up}} \]
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