Gauss Law. Please use the formula I added. 3. A Gaussian surface is a closed surface in three-dimensional space through whichthe electric flux is calculated. Given a spherical Gaussian surface that has aradius of 0.5 meters and encloses 30 electrons.A. Find the value of the electric flux through this surfaceB. From the calculated value of the electric flux, determine the value of theelectric field at a distance equal to 0.6 meters from the center of the surface. Gauss' Law describes the relationship between a charge distribution and the electric field it produces. This law wasformulated by the Geman mathematician and physicist Carl Friedrich Gauss (1777-1855). In presenting Gauss' law,it will be necessary to introduce a new idea called electric flux. The idea of flux involves both the electric field andthe surface through which it passes. By bringing together the electric field and the surface through which it passes,we will be able to define electric flux and then present Gauss' law.> E= where k=-> Hypothetical closed surface, Gaussian surface> For a spherical surface, A= 4r?, E= -permittivity if free space4Cor2NormalE=E cos4R€Or2€04ar2Gauss' Law for Point ChargeE=A€0A> E= 4EA= 4Electric flux DEA€0In general, surface - arbitrary shape but closed; EnetaNot necessarily I to the Gaussian surface; magnitudeNeed not be constant (vary from point to point)ChargedistributionDE = I (Enats-) AA= E (E cosØ) AAGaussiansurface

Answered: Image /qna-images/answer/8cd02621-4419-49ab-bef2-e9778f6e6c3b.jpg

3. A Gaussian surface is a closed surface in three-dimensional space through which the electric flux is calculated. Given a spherical Gaussian surface that has a radius of 0.5 meters and encloses 30 electrons. A. Find the value of the electric flux through this surface B. From the calculated value of the electric flux, determine the value of the electric field at a distance equal to 0.6 meters from the center of the surface.

3. A Gaussian surface is a closed surface in three-dimensional space through which the electric flux is calculated. Given a spherical Gaussian surface that has a radius of 0.5 meters and encloses 30 electrons. A. Find the value of the electric flux through this surface B. From the calculated value of the electric flux, determine the value of the electric field at a distance equal to 0.6 meters from the center of the surface.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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