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3. A cylindrical rod is fixed between two walls. The rod is composed of two materials. Section AC is made of one material (GaC = 2G) while section CD is made of a different material (GcD = G). A torque, T, is applied at point B, as shown below. Jac = JcD = J = 2 in. GẠC = 2G = 20 x 10ʻ psi T= 300 kip in. GcD = G = 10 x 10 psi B D 2L Determine the reactions at the wall, TA, and Tp. Specify the direction for each. (Note: this is an example of a no calculator problem.) Ans: TA = 250 kip in ( TD= 50 kip in Fixed Fixed to wall to wall

3. A cylindrical rod is fixed between two walls. The rod is composed of two materials. Section AC is made of one material (GaC = 2G) while section CD is made of a different material (GcD = G). A torque, T, is applied at point B, as shown below. Jac = JcD = J = 2 in. GẠC = 2G = 20 x 10ʻ psi T= 300 kip in. GcD = G = 10 x 10 psi B D 2L Determine the reactions at the wall, TA, and Tp. Specify the direction for each. (Note: this is an example of a no calculator problem.) Ans: TA = 250 kip in ( TD= 50 kip in Fixed Fixed to wall to wall

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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3. A cylindrical rod is fixed between two walls. The rod is composed of two materials. Section AC is made of one material (GAC = 2G) while section CD is made of a different material (GcD = G). A torque, T, is applied at point B, as shown below. Jac = JcD = J = 2 in. GẠC = 2G = 20 x 10ʻ psi T= 300 kip in. GCD = G = 10 × 106 psi A D 2L Determine the reactions at the wall, Ta, and Tp. Specify the direction for each. (Note: this is an example of a no calculator problem.) Ans: TA = 250 kip in ( Tp=50 kip in ( T Fixed Fixed to wall to wall
Transcribed Image Text:3. A cylindrical rod is fixed between two walls. The rod is composed of two materials. Section AC is made of one material (GAC = 2G) while section CD is made of a different material (GcD = G). A torque, T, is applied at point B, as shown below. Jac = JcD = J = 2 in. GẠC = 2G = 20 x 10ʻ psi T= 300 kip in. GCD = G = 10 × 106 psi A D 2L Determine the reactions at the wall, Ta, and Tp. Specify the direction for each. (Note: this is an example of a no calculator problem.) Ans: TA = 250 kip in ( Tp=50 kip in ( T Fixed Fixed to wall to wall
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