3. a current-carrying Loop with of -~-9 = 0.120m and a length of b=0.200m turns on an Ayle due to Torque. A current travels countur -clockwish the Uniform maqnetic field of B² = 0.25oT is present as depicted in the Diagram. I = 3.0 A 7 Axle Find: a.) Magnitude of the Force on the Left and of Right segments the loopo 6) Indicate on the diagram the direction of the Torque on the left and Right segments either O. (Left width Sh Malone a-l 120 m O C.) Magnitude of the Top & bottom of the loop. to oth d.) Find the maximum Torque on the Loop TH 20 m 5 (Right) a) left F=Bilsina F= (0.250T) (3:0A)(20m) sin (90) -0.15N F= 0.15 N up ab 21 d) π = NBIAsin = right X ✓ F=Bilsine F=(0.250T) (3.0)(20m) Sin (90) A=Lxw = 0,024m T= (0.250T) (3.0A)(. 120m x.20m) sin 90 =0.018N·m (= ?

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Chapter1: Units, Trigonometry. And Vectors
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3.) a current-carrying Loop with a
9 = 0.120m and
with a width
of
length of b=0.200m turns on
an Axle due to Torque. A current travels countur -clockwise
the Uniform maqnetic field
R=
O.ZsoT is present as
a
of
depicted in the Diagram. I = 3,0 A
FIND :
a.) Magnitude of the
Force on the Left and
Right segments of
the loop.
6) Indicate on the diagram
the direction of the Torque
on the left and Right segments
either or O.
a) left
F=Bilsina
F= (0.250T) (3.0A) (,20m) sin (90) 0.15N
ته از تولید
eft
2,
d) T
d) - NB IAsino
C.) Magnitude of the Top & bottom of the Loop.
d.) Find the maximum Torque on the loop
MAT C
98
Motorna
O
Axle
I
L. I
A
a l
120 m
O
right
.20m
O
I b (Right)
F
O
for
4 both
X
î♡
A=Lxw = 0,024m
~=
↑= (0.250T) (3.0A)(. 120m x.20m) sin 90 = 10.018 N·m
(= 7
O
F=BIlsin+
F=(0.250T) (3,07) (.20m) Sin (90)
F = 0.15 N
Transcribed Image Text:3.) a current-carrying Loop with a 9 = 0.120m and with a width of length of b=0.200m turns on an Axle due to Torque. A current travels countur -clockwise the Uniform maqnetic field R= O.ZsoT is present as a of depicted in the Diagram. I = 3,0 A FIND : a.) Magnitude of the Force on the Left and Right segments of the loop. 6) Indicate on the diagram the direction of the Torque on the left and Right segments either or O. a) left F=Bilsina F= (0.250T) (3.0A) (,20m) sin (90) 0.15N ته از تولید eft 2, d) T d) - NB IAsino C.) Magnitude of the Top & bottom of the Loop. d.) Find the maximum Torque on the loop MAT C 98 Motorna O Axle I L. I A a l 120 m O right .20m O I b (Right) F O for 4 both X î♡ A=Lxw = 0,024m ~= ↑= (0.250T) (3.0A)(. 120m x.20m) sin 90 = 10.018 N·m (= 7 O F=BIlsin+ F=(0.250T) (3,07) (.20m) Sin (90) F = 0.15 N
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