**Problem Statement**A converging lens with a focal length of 12 cm is placed at the center of a flat-end cylindrical glass tube of length 24 cm. The lens forms an insulated, airtight seal that creates two chambers of equal volume, allowing it to slide like a piston within the cylinder. A mole of helium is injected into the left chamber, and a mole of molecular (diatomic) hydrogen is injected into the right chamber. Both chambers are initially at the same temperature. The lens is at \( x = 0 \) in the coordinate system. See the "before" picture below:**Illustration Description**- **Before State:** - Two chambers are separated by the lens. - The left chamber (He) has helium. - The right chamber (H₂) has hydrogen. - Both gases are shown with equal positions \( x = -12 \, \text{cm} \) to \( x = +12 \, \text{cm} \).- **After State:** - The diagram shows the lens moving, with helium and hydrogen on the respective sides and indicates a shift in position labeled \( x = ? \).**Conditions**With equal volumes and equal numbers of moles of ideal gases at equal temperatures, the pressures are initially equal, so the lens/piston doesn’t move initially. An external observer looks through the left end of the cylinder at an object on the right side, seeing its image at position \(-84 \, \text{cm}\).Additional assumptions:- Index of refraction for the gases is 1 (doesn't affect lens focal length).- No major temperature variations induce different gas modes.**Questions**a) Heat is added to one of the gases to equalize the internal energies. Determine which chamber receives the heat and why.b) Demonstrate that the lens moves 3.0 cm from its original position as the internal energies equalize. Indicate the movement direction.c) Compute the new position \( x \) of the image after the lens moves.

Given that: Initial temperature of the system is T1=T2Object position, xo=+12 cmImage position,…

3. A converging lens with a focal length of 12 cm is placed at the center of a flat-end cylindrical glass tube of length 24 cm. The lens forms an insulated, airtight seal that creates two chambers of equal volume, and is free to slide like a piston within the cylinder. A mole of helium is injected into the left chamber, and a mole of molecular (diatomic) hydrogen is injected into the right chamber, and both chambers of gas are at the same temperature. A coordinate system with the lens at x = 0 has been introduced to simplify calculations (see "before" picture below). you before (T₁=T₂, lens at x=0, image at x=-84cm) x=-12cm He x=0cm H₂ x=+12cm after (U₁=U₂, lens at x=?, image at x=?) x=-12cm He x=0cm H₂ x=+12cm With the equal-volume chambers enclosing equal numbers of moles of ideal gases at equal temperatures, the pressures must also be equal, which means the lens/piston doesn't move. You look through the left end of this cylinder at an object that is on the right side of the cylinder, and see its image at position -84 cm. Assume throughout that the gases have an index of refraction equal to 1, and therefore don't affect the focal length of the lens. Also assume that neither gas gets sufficiently hot or cold to have modes available that are different from when they are at room temperature. a. Heat is added to one of the two gases until the internal energies of the gases are equal. To which chamber does heat need to be added for the internal energies to be equal? Explain. b. Show that the lens moves 3.0cm from its original position when the two gases reach equal amounts of internal energy, and determine the direction it moves. c. Find the new position (z value) of the image after the lens has moved.

3. A converging lens with a focal length of 12 cm is placed at the center of a flat-end cylindrical glass tube of length 24 cm. The lens forms an insulated, airtight seal that creates two chambers of equal volume, and is free to slide like a piston within the cylinder. A mole of helium is injected into the left chamber, and a mole of molecular (diatomic) hydrogen is injected into the right chamber, and both chambers of gas are at the same temperature. A coordinate system with the lens at x = 0 has been introduced to simplify calculations (see "before" picture below). you before (T₁=T₂, lens at x=0, image at x=-84cm) x=-12cm He x=0cm H₂ x=+12cm after (U₁=U₂, lens at x=?, image at x=?) x=-12cm He x=0cm H₂ x=+12cm With the equal-volume chambers enclosing equal numbers of moles of ideal gases at equal temperatures, the pressures must also be equal, which means the lens/piston doesn't move. You look through the left end of this cylinder at an object that is on the right side of the cylinder, and see its image at position -84 cm. Assume throughout that the gases have an index of refraction equal to 1, and therefore don't affect the focal length of the lens. Also assume that neither gas gets sufficiently hot or cold to have modes available that are different from when they are at room temperature. a. Heat is added to one of the two gases until the internal energies of the gases are equal. To which chamber does heat need to be added for the internal energies to be equal? Explain. b. Show that the lens moves 3.0cm from its original position when the two gases reach equal amounts of internal energy, and determine the direction it moves. c. Find the new position (z value) of the image after the lens has moved.