3. A 32.65 g metal is placed in a flask. Liquid toluene is added to the flask so that the total volume of the metal and liquid toluene together is 50.00 mL. The metal and toluene together weigh 58.58 g. The density of toluene at the temperature of the experiment is 0.8640 g/mL. What is the density of the metal?

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**Problem Statement:**

A 32.65 g metal is placed in a flask. Liquid toluene is added to the flask so that the total volume of the metal and liquid toluene together is 50.00 mL. The metal and toluene together weigh 58.58 g. The density of toluene at the temperature of the experiment is 0.8640 g/mL. What is the density of the metal?

**Solution Approach:**

1. **Determine the Mass of the Toluene:**
   - Total mass (metal + toluene) = 58.58 g
   - Mass of the metal = 32.65 g
   - Mass of the toluene = 58.58 g - 32.65 g = 25.93 g

2. **Calculate the Volume of the Toluene:**
   - Using the density of toluene, \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
   - Volume of toluene = \(\frac{25.93 \, \text{g}}{0.8640 \, \text{g/mL}} \approx 30.01 \, \text{mL} \)

3. **Volume of the Metal:**
   - Total volume (metal + toluene) = 50.00 mL
   - Volume of the metal = 50.00 mL - 30.01 mL = 19.99 mL

4. **Calculate the Density of the Metal:**
   - Using the density formula, \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
   - Density of the metal = \(\frac{32.65 \, \text{g}}{19.99 \, \text{mL}} \approx 1.63 \, \text{g/mL} \)

Therefore, the density of the metal is approximately \(1.63 \, \text{g/mL}\).
Transcribed Image Text:**Problem Statement:** A 32.65 g metal is placed in a flask. Liquid toluene is added to the flask so that the total volume of the metal and liquid toluene together is 50.00 mL. The metal and toluene together weigh 58.58 g. The density of toluene at the temperature of the experiment is 0.8640 g/mL. What is the density of the metal? **Solution Approach:** 1. **Determine the Mass of the Toluene:** - Total mass (metal + toluene) = 58.58 g - Mass of the metal = 32.65 g - Mass of the toluene = 58.58 g - 32.65 g = 25.93 g 2. **Calculate the Volume of the Toluene:** - Using the density of toluene, \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] - Volume of toluene = \(\frac{25.93 \, \text{g}}{0.8640 \, \text{g/mL}} \approx 30.01 \, \text{mL} \) 3. **Volume of the Metal:** - Total volume (metal + toluene) = 50.00 mL - Volume of the metal = 50.00 mL - 30.01 mL = 19.99 mL 4. **Calculate the Density of the Metal:** - Using the density formula, \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] - Density of the metal = \(\frac{32.65 \, \text{g}}{19.99 \, \text{mL}} \approx 1.63 \, \text{g/mL} \) Therefore, the density of the metal is approximately \(1.63 \, \text{g/mL}\).
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