3. A 12 ft, 20 lb seesaw is balanced by a little girl (60 lb) and her father (180 lb) at opposite ends as shown below. How far from the seesaw's center of mass must the fulcrum be placed? 60lb 201b 12ft K 180lb
3. A 12 ft, 20 lb seesaw is balanced by a little girl (60 lb) and her father (180 lb) at opposite ends as shown below. How far from the seesaw's center of mass must the fulcrum be placed? 60lb 201b 12ft K 180lb
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Question
![T
CW
T
3. A 12 ft, 20 lb seesaw is balanced by a little girl (60 lb) and her father (180 lb) at opposite
ends as shown below. How far from the seesaw's center of mass must the fulcrum be
placed?
CCW
0
A
60lb
T = 60* (x + 6) +20 * x = 80x + 360
CCW
201b
X
= 180 (6-x) = 1080 - 180x
= Tw
12ft
180lb
80x + 360 = 1080 - 180xx=2.77 ft.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3ebc26e-28a0-426e-bac7-61c517215e28%2Fe76ed99f-ffc2-46ea-9251-117e8dbac643%2Fx8p2ymm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:T
CW
T
3. A 12 ft, 20 lb seesaw is balanced by a little girl (60 lb) and her father (180 lb) at opposite
ends as shown below. How far from the seesaw's center of mass must the fulcrum be
placed?
CCW
0
A
60lb
T = 60* (x + 6) +20 * x = 80x + 360
CCW
201b
X
= 180 (6-x) = 1080 - 180x
= Tw
12ft
180lb
80x + 360 = 1080 - 180xx=2.77 ft.
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