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3 x² + y² the direction of (−3, −3). Then, Suppose f(x, y) (a) ▼ ƒ (x, y) (b) ▼ ƒ(1,4) = = = 1/77 (-6i - 24j) (c) ƒu (1, 4) = Du ƒ(1,4) and u is the unit vector in =

3 x² + y² the direction of (−3, −3). Then, Suppose f(x, y) (a) ▼ ƒ (x, y) (b) ▼ ƒ(1,4) = = = 1/77 (-6i - 24j) (c) ƒu (1, 4) = Du ƒ(1,4) and u is the unit vector in =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Suppose \( f(x, y) = \frac{3}{x^2 + y^2} \) and \(\mathbf{u}\) is the unit vector in the direction of \(\langle -3, -3 \rangle\). Then, (a) \(\nabla f(x, y) = \) [ ] (b) \(\nabla f(1, 4) = \frac{1}{17} (-6\mathbf{i} - 24\mathbf{j})\) (c) \(f_u(1, 4) = D_u f(1, 4) = \) [ ]
Transcribed Image Text:Suppose \( f(x, y) = \frac{3}{x^2 + y^2} \) and \(\mathbf{u}\) is the unit vector in the direction of \(\langle -3, -3 \rangle\). Then, (a) \(\nabla f(x, y) = \) [ ] (b) \(\nabla f(1, 4) = \frac{1}{17} (-6\mathbf{i} - 24\mathbf{j})\) (c) \(f_u(1, 4) = D_u f(1, 4) = \) [ ]
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