[3] Water flows through the system of pipes shown in the figure below. Ve=0.9[m/s] 2 1 P=1atm h = 2.5(m] The cross-sectional areas of the two pipes are A= 25x [cm² ] , a =9x [cm² ] •
[3] Water flows through the system of pipes shown in the figure below. Ve=0.9[m/s] 2 1 P=1atm h = 2.5(m] The cross-sectional areas of the two pipes are A= 25x [cm² ] , a =9x [cm² ] •
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Problem 1.1MA
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![[3] Water flows through the system of pipes shown in the figure below.
Ve=0.9[m/s] 2
Da
P=1atm
h = 2.5[m]
The cross-sectional areas of the two pipes are A=257[cm°] ,a =9z[cm° ] .
(a) Calculate the pressures P, & P, at the center of the pipes at points 2 (just prior to the
constriction) and 3 (at the lower elevation)., and velocities at the center of the lower pipe
(v.) and the center of the small pipe at the exit (v ).
(b) The total length of the large diameter pipe is 6 meters and the small pipe is 1.5 meters
long. We now consider the effects of viscosity. In order to maintain the same volume flow
dv
= av, , what pressure difference must exist between
dt
rate as for the non-viscous case,
the two ends of the small diameter pipe? What is the pressure at the restriction then?
(c) Furthering our investigation, we now consider the large diameter pipe. For Bernoulli's
law (no viscosity) how did the volume flow rates compare for the upper and lower pipes?
Now with viscosity and the 6[m] length, what pressure difference is necessary to keep
that flow rate the same?
(d) What happens to the pressure difference due to the height? What does this give as
the total pressure difference between point 3 at the bottom and the constriction at point
2? Explain the reasoning behind your answer.
(e) A student makes the statement that "If there were no flow (a nozzle at the top is
closed), the pressure would be the same in all parts of the system." Do you agree with the
student or not and explain your reasoning.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9de2b0ed-01a2-4a8a-9b30-8cd619de91d2%2Fc9d5bf8a-2828-4fd6-aaeb-31c02e3c42bf%2F3ttyfjn_processed.png&w=3840&q=75)
Transcribed Image Text:[3] Water flows through the system of pipes shown in the figure below.
Ve=0.9[m/s] 2
Da
P=1atm
h = 2.5[m]
The cross-sectional areas of the two pipes are A=257[cm°] ,a =9z[cm° ] .
(a) Calculate the pressures P, & P, at the center of the pipes at points 2 (just prior to the
constriction) and 3 (at the lower elevation)., and velocities at the center of the lower pipe
(v.) and the center of the small pipe at the exit (v ).
(b) The total length of the large diameter pipe is 6 meters and the small pipe is 1.5 meters
long. We now consider the effects of viscosity. In order to maintain the same volume flow
dv
= av, , what pressure difference must exist between
dt
rate as for the non-viscous case,
the two ends of the small diameter pipe? What is the pressure at the restriction then?
(c) Furthering our investigation, we now consider the large diameter pipe. For Bernoulli's
law (no viscosity) how did the volume flow rates compare for the upper and lower pipes?
Now with viscosity and the 6[m] length, what pressure difference is necessary to keep
that flow rate the same?
(d) What happens to the pressure difference due to the height? What does this give as
the total pressure difference between point 3 at the bottom and the constriction at point
2? Explain the reasoning behind your answer.
(e) A student makes the statement that "If there were no flow (a nozzle at the top is
closed), the pressure would be the same in all parts of the system." Do you agree with the
student or not and explain your reasoning.
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