3 V 10 k2 30 k2 5.4 V 20 k2 +, 3.9 V Vo 30 k2 + Q+
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5.37 Determine the output of the summing amplifier in Fig. 5.74.
![### Operational Amplifier Inverting Summing Amplifier Circuit
This diagram illustrates an inverting summing amplifier using an operational amplifier (op-amp). Here's a detailed breakdown of the components and their connections:
#### Components
1. **Voltage Sources**:
- **3 V** source connected through a **10 kΩ** resistor.
- **5.4 V** source connected through a **20 kΩ** resistor.
- **3.9 V** source connected through a **30 kΩ** resistor.
2. **Resistors**:
- Input resistors: 10 kΩ, 20 kΩ, and 30 kΩ connected to respective voltage sources.
- Feedback resistor: **30 kΩ** connected from the output to the inverting input of the op-amp.
3. **Operational Amplifier**:
- Inverts and sums the input voltages.
- The inverting input is connected to all input resistors, and feedback is provided through the 30 kΩ resistor.
- Non-inverting input is grounded.
4. **Output**:
- The output voltage (\(V_o\)) is designated at the op-amp's output terminal, which is referenced to ground.
#### Functionality
The circuit sums the input voltages, each weighted by the inverse of their corresponding resistance, and inverts the result. The output voltage (\(V_o\)) is determined by the formula:
\[ V_o = - \left( \frac{V_1}{R_1} + \frac{V_2}{R_2} + \frac{V_3}{R_3} \right) \times R_f \]
Where:
- \(V_1 = 3 \, \text{V}\), \(R_1 = 10 \, \text{kΩ}\)
- \(V_2 = 5.4 \, \text{V}\), \(R_2 = 20 \, \text{kΩ}\)
- \(V_3 = 3.9 \, \text{V}\), \(R_3 = 30 \, \text{kΩ}\)
- \(R_f = 30 \, \text{kΩ}\) (feedback resistor)
This configuration showcases a basic application of operational amplifiers in electronics, particularly useful in analog signal processing for combining signals.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff57c5c9b-acb3-4a3d-a39b-55eeff7ee4ad%2F2734cd89-bc95-41e3-8559-b48ab84aae37%2Fuvsiokw_processed.png&w=3840&q=75)
Transcribed Image Text:### Operational Amplifier Inverting Summing Amplifier Circuit
This diagram illustrates an inverting summing amplifier using an operational amplifier (op-amp). Here's a detailed breakdown of the components and their connections:
#### Components
1. **Voltage Sources**:
- **3 V** source connected through a **10 kΩ** resistor.
- **5.4 V** source connected through a **20 kΩ** resistor.
- **3.9 V** source connected through a **30 kΩ** resistor.
2. **Resistors**:
- Input resistors: 10 kΩ, 20 kΩ, and 30 kΩ connected to respective voltage sources.
- Feedback resistor: **30 kΩ** connected from the output to the inverting input of the op-amp.
3. **Operational Amplifier**:
- Inverts and sums the input voltages.
- The inverting input is connected to all input resistors, and feedback is provided through the 30 kΩ resistor.
- Non-inverting input is grounded.
4. **Output**:
- The output voltage (\(V_o\)) is designated at the op-amp's output terminal, which is referenced to ground.
#### Functionality
The circuit sums the input voltages, each weighted by the inverse of their corresponding resistance, and inverts the result. The output voltage (\(V_o\)) is determined by the formula:
\[ V_o = - \left( \frac{V_1}{R_1} + \frac{V_2}{R_2} + \frac{V_3}{R_3} \right) \times R_f \]
Where:
- \(V_1 = 3 \, \text{V}\), \(R_1 = 10 \, \text{kΩ}\)
- \(V_2 = 5.4 \, \text{V}\), \(R_2 = 20 \, \text{kΩ}\)
- \(V_3 = 3.9 \, \text{V}\), \(R_3 = 30 \, \text{kΩ}\)
- \(R_f = 30 \, \text{kΩ}\) (feedback resistor)
This configuration showcases a basic application of operational amplifiers in electronics, particularly useful in analog signal processing for combining signals.
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