(3) Using the appropriate approach covered in Unit 6 of this Course along with knowledge gained in Unit 1 and 2, show that: 1 h 4 (a) Lim х — 1 x+1 = -2 (b) Ļim h-0 V5h + 4 –- 2 X-0 X t3 – 1 -= 3. (c) Lim- t-1 t-1

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A:

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A:

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A:

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A: This question can be solved using the concept of function and rationalization.

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.