3) Use the definition of the derivative (which involves limits) to calculate f'(2) given that f(x) = (x - 2)² +5. No shortcuts. To get credit, you must use the definition and show all work clearly. Be sure to use complete notation and put limits where necessary

Q: f(x) = x² - 2x + 1

A:

Q: f(x) = 3x² - 5x+21

A: SOLUTION-

Q: 5 8 72 ex

A: Given f( x ) = ( x )72ex5

Q: Find the equation of the tangent line to the function f(x)= x^3-4x at the point where x=0. Do not…

A: Here first we find the slope using the formula m=f'0 Then equation of the tangent at point x = 0,…

Q: 5 4x +5x7 Find the derivative of the function f(x)=- 2x² 20 (1) Quotient Rule and (2) simplify first…

A:

Q: For the following function, describe the concavity and find relative extrem using the concavity test…

A:

Q: Find the derivative of f(x) = √5 - 4x. To enter √a, type sqrt(a). f (2)

A: The objective objective is to find f'(x).

Q: Find the derivative of the 1 f(x) = x5 + (x² + 7)(x² – x – 2) + 17 5.

A: Given: fx=15x5+x2+7x2-x-2+17

Q: Given functions f and g for which f(- 6) = 1, ƒ'( – 6) = 1, g( – 6) = 6, and g'(- 6) = 2. Evaluate…

A:

Q: 1. Find the first derivative formula for each function. In each case tak with respect to the…

A:

Q: Use the sum and/or difference rule(s) to find the derivative of the following functions: with…

A: We have to find derivative of given function.

Q: a).Find x value where the graph has a horizontal tangent line. f(x) = x^3 + x Using the fact that…

A: The given function is  f(x) = x3 + x Differentiate with respect to x , we get f'(x) = 3x2 + 1

Q: b. g(x)=√x + ²3 marks) X

A: The solution is given by

Q: 34. Draw the graph of the derivative. The graph of f (x) is provided.

A: Given

Q: Use the quotient rule to find the derivative of - 8 sin(x) + 2 | 3x4 + 6

A: We need to evaluate the derivative of the following function -8sin(x)+23x4+6

Q: Find the derivative f(x)= Inlex+9)

A: To find: the derivative of f(x)

Q: Please find the derivative of the algebraic function below using the Quotient rule. No chain rule…

A: