only D E F G 3 Under acid conditions propanone can be brominated. The stoichiometric equation for thisreaction is:H'(aq)CH,COCH,(aq) + Br,(aq)-CH,COCH,Br(aq) + H'(aq) + Br(aq)The following experimental data gives the initial rate of the reaction at particular concentrations.Experimentnumber123[CH,COCH,(aq))/ mol dm2.0 x 102.0 x 101.0 x 101.0 x 101.7 x 10[Br,(aq)]/ mol dm5.0 x 101.0 x 105.0 x 105.0х 10*2.2 x 10[H'(aq)]/ mol dm5.0 x 105.0 x 105.0 x 101.0 x 102.9 x 10Initial rate/ mol dm s5.0 x 10*5.0 x 102.5 x 105.0 x 104(a) Deduce the order of the reaction with respect to propanone.(b) Deduce the order of the reaction with respect to bromine.(c) Deduce the order of the reaction with respect to hydrogen ions.(d) Deduce the overall order of the reaction.(e) Write the rate expression for this reaction.(f) Calculate the value for the rate constant.(g) Calculate the initial rate of reaction for experiment number 5.

The rate law of a chemical reaction provides a relationship between the rate of the reaction and…

3 Under acid conditions propanone can be brominated. The stoichiometric equation for this reaction is: H'(aq) CH,COCH,(aq) + Br;(aq). + CH,COCH,Br(aq) + H*(aq) + Br (aq) The following experimental data gives the initial rate of the reaction at particular concentrations. [H'(aq)] / mol dm 5.0 x 10 5.0 x 10 5.0 x 10 1.0 x 10 Experiment number [CH,COCH,(aq)] / mol dm 2.0 x 10 2.0 x 10 1.0 x 10 1.0 x 10 [Br,(aq)] / mol dm 5.0 x 10 1.0 x 10 5.0 x 10 5.0 x 10 Initial rate / mol dms 5.0 x 10 5.0 x 10 2.5 x 10 5.0 x 10 -3-1 1 2 3 4

3 Under acid conditions propanone can be brominated. The stoichiometric equation for this reaction is: H'(aq) CH,COCH,(aq) + Br;(aq). + CH,COCH,Br(aq) + H*(aq) + Br (aq) The following experimental data gives the initial rate of the reaction at particular concentrations. [H'(aq)] / mol dm 5.0 x 10 5.0 x 10 5.0 x 10 1.0 x 10 Experiment number [CH,COCH,(aq)] / mol dm 2.0 x 10 2.0 x 10 1.0 x 10 1.0 x 10 [Br,(aq)] / mol dm 5.0 x 10 1.0 x 10 5.0 x 10 5.0 x 10 Initial rate / mol dms 5.0 x 10 5.0 x 10 2.5 x 10 5.0 x 10 -3-1 1 2 3 4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

only D E F G

3 Under acid conditions propanone can be brominated. The stoichiometric equation for this
reaction is:
H'(aq)
CH,COCH,(aq) + Br,(aq)-
CH,COCH,Br(aq) + H'(aq) + Br(aq)
The following experimental data gives the initial rate of the reaction at particular concentrations.
Experiment
number
1
2
3
[CH,COCH,(aq))
/ mol dm
2.0 x 10
2.0 x 10
1.0 x 10
1.0 x 10
1.7 x 10
[Br,(aq)]
/ mol dm
5.0 x 10
1.0 x 10
5.0 x 10
5.0х 10*
2.2 x 10
[H'(aq)]
/ mol dm
5.0 x 10
5.0 x 10
5.0 x 10
1.0 x 10
2.9 x 10
Initial rate
/ mol dm s
5.0 x 10*
5.0 x 10
2.5 x 10
5.0 x 10
4
(a) Deduce the order of the reaction with respect to propanone.
(b) Deduce the order of the reaction with respect to bromine.
(c) Deduce the order of the reaction with respect to hydrogen ions.
(d) Deduce the overall order of the reaction.
(e) Write the rate expression for this reaction.
(f) Calculate the value for the rate constant.
(g) Calculate the initial rate of reaction for experiment number 5.

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AutoSave We hw OFF ... Home Insert Draw Design Layout References Mailings Review View O Tell me R Share O Comments Calibri (Bo.. v 11 v A A E vE v E v E E Aa v AaBbCcDdEe AaBbCcD AaBbCcDdE AaBb AaBbCcDdEe BIU V ab A • I v A v Paste х, х E= == No Spacing Normal Heading 1 Heading 2 Title Styles Pane Dictate Sensitivity C13 NMR Peaks Aldehydes RCO)R Aldehydes and ketones Carbaxylic R(CO)X Carbaxylic acid derivatives Ntrile Nitrile RCN CC C-C Alkyne Akyne R-CC-R RCH20 RCH2-O R4C RAC R3CH R3CH RCH2X X= C-C, C-O, Br, CI, N RCH2X R2CH2 RECH2 RCH3 RCH3 TMS TMS 220 200 180 160 140 120 100 80 60 40 20 Typical chemical shifts in 13c-NMR 9) Why do the peaks of associated with aldehydes (both in H NMR and C NMR) appear so much further downfield than other peaks? C13 NMR Peaks E Page 5 of 5 E English (United States) O Focus 295 words 白

In the glucose molecule, why is the oxygen at carbon 5 the one that reacts with carbon 1 when there is an additional carbon at the end of the chain, carbon 6? t Predictions: On a. Due to the chirality of the last carbon, carbon 6 b. Because carbon 5 is the last chiral carbon 4 C. Because the oxygen at carbon 5 is in alpha position just like the oxygen at carbon 1 Accessibility: Good to go O 8: 14 101 f5 % 5 f6 A 17 40 & 7 18 Ö 7 W f9 8 8 f10 9 19 11 F ) O n f12 81°F Cla