3) The table below describes the smoking habits of a group of asthma sufferers. Occasional Regular Heavy Nonsmoker smoker smoker smoker Total Men 339 33 61 34 467 Women 377 32 84 36 529 Total 716 65 145 70 996 If one of the 996 people is randomly selected, find the probability of getting a regular or heavy smoker. A) 0.146 B) 0.216 C) 0.095 D) 0.442 the indicated complement. 4) The probability that Luis will pass his statistics test is 0.90. Find the probability that he will fail his statistics test. A) 9.00 B) 1.11 C) 0.10 D) 0.45

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**Probability and Statistics Exercise**

This exercise involves calculating probability based on provided data and understanding complementary probabilities. There are also tabular data and related probabilistic questions requiring interpretation.

**Tabular Data:**
The table below presents information on cigarette consumption categorized by gender.

| Cigarette Consumption per Day | Men   | Women | Total |
|------------------------------|-------|-------|-------|
| None                         | 339   | 377   | 716   |
| 1-9                          | 61    | 34    | 95    |
| 10-19                        | 36    | 32    | 68    |
| 20-39                        | 31    | 22    | 53    |
| 40+                          | 0     | 70    | 70    |
| **Total**                    | 467   | 529   | 996   |

**Probability Questions:**

1. **If one of the 996 people is randomly selected, find the probability of getting a regular or heavy smoker.**

    Options:
    - A) 0.146
    - B) 0.216
    - C) 0.095
    - D) 0.442

2. **If one of the 996 people is randomly selected, find the probability that he will fail his statistics test.**

    Options:
    - A) 9.00
    - B) 1.11
    - C) 0.10
    - D) 0.45

**Question Explanations:**

- **Question 1 Explanation:**
    - Involves determining the probability of selecting a regular or heavy smoker from the group.
    - Sum the number of regular smokers (defined as those who smoke 1-9, 10-19, or 20-39 cigarettes per day) and heavy smokers (defined as those who smoke 40+ cigarettes per day).
    - Divide the sum by the total number of people (996).

- **Question 2 Explanation:**
    - The problem states, "The probability that Luis will pass his statistics test is 0.90. Find the probability that he will fail his statistics test."
    - This is finding the complement of the probability of passing the test.
    - The complement is calculated as 1 - Probability of passing.

By working through these questions, students will learn to interpret and use
Transcribed Image Text:**Probability and Statistics Exercise** This exercise involves calculating probability based on provided data and understanding complementary probabilities. There are also tabular data and related probabilistic questions requiring interpretation. **Tabular Data:** The table below presents information on cigarette consumption categorized by gender. | Cigarette Consumption per Day | Men | Women | Total | |------------------------------|-------|-------|-------| | None | 339 | 377 | 716 | | 1-9 | 61 | 34 | 95 | | 10-19 | 36 | 32 | 68 | | 20-39 | 31 | 22 | 53 | | 40+ | 0 | 70 | 70 | | **Total** | 467 | 529 | 996 | **Probability Questions:** 1. **If one of the 996 people is randomly selected, find the probability of getting a regular or heavy smoker.** Options: - A) 0.146 - B) 0.216 - C) 0.095 - D) 0.442 2. **If one of the 996 people is randomly selected, find the probability that he will fail his statistics test.** Options: - A) 9.00 - B) 1.11 - C) 0.10 - D) 0.45 **Question Explanations:** - **Question 1 Explanation:** - Involves determining the probability of selecting a regular or heavy smoker from the group. - Sum the number of regular smokers (defined as those who smoke 1-9, 10-19, or 20-39 cigarettes per day) and heavy smokers (defined as those who smoke 40+ cigarettes per day). - Divide the sum by the total number of people (996). - **Question 2 Explanation:** - The problem states, "The probability that Luis will pass his statistics test is 0.90. Find the probability that he will fail his statistics test." - This is finding the complement of the probability of passing the test. - The complement is calculated as 1 - Probability of passing. By working through these questions, students will learn to interpret and use
### Probability Study Questions on Asthma Sufferers' Smoking Habits

#### Problem 3
A study was conducted to examine the smoking habits of asthma sufferers. The data collected is summarized in the table below, showing the number of individuals who are nonsmokers, occasional smokers, regular smokers, and heavy smokers, divided by gender.

| Gender  | Smoking Habit       | Count  |
|---------|---------------------|--------|
| Men     | Nonsmoker           | 339    |
|         | Occasional smoker   | 33     |
|         | Regular smoker      | 61     |
|         | Heavy smoker        | 34     |
| **Total** |                   | **467**|
| Women   | Nonsmoker           | 377    |
|         | Occasional smoker   | 32     |
|         | Regular smoker      | 84     |
|         | Heavy smoker        | 36     |
| **Total** |                   | **529**|
| **Total** | Nonsmoker         | **716**|
|         | Occasional smoker   | **65** |
|         | Regular smoker      | **145**|
|         | Heavy smoker        | **70** |
| **Grand Total** |             | **996**|

#### Tasks Based on the Data

**Question:** If one of the 996 people is randomly selected, find the probability of getting a regular or heavy smoker.
- A) 0.146
- B) 0.216
- C) 0.095
- D) 0.442

**Solution Approach:**
1. Calculate the total number of regular and heavy smokers combined.
   - Regular smokers: 145
   - Heavy smokers: 70
   - Total regular or heavy smokers = 145 + 70 = 215

2. Calculate the probability:
   \[
   P(\text{Regular or Heavy Smoker}) = \frac{\text{Number of Regular or Heavy Smokers}}{\text{Total Individuals}} = \frac{215}{996}
   \]

3. Simplify the fraction:
   \[
   P = \frac{215}{996} \approx 0.216 \quad \text{(after rounding to three decimal places)}
   \]

**Answer:** 
- The correct option is (B) 0.216.

This table and solution help illustrate how to calculate
Transcribed Image Text:### Probability Study Questions on Asthma Sufferers' Smoking Habits #### Problem 3 A study was conducted to examine the smoking habits of asthma sufferers. The data collected is summarized in the table below, showing the number of individuals who are nonsmokers, occasional smokers, regular smokers, and heavy smokers, divided by gender. | Gender | Smoking Habit | Count | |---------|---------------------|--------| | Men | Nonsmoker | 339 | | | Occasional smoker | 33 | | | Regular smoker | 61 | | | Heavy smoker | 34 | | **Total** | | **467**| | Women | Nonsmoker | 377 | | | Occasional smoker | 32 | | | Regular smoker | 84 | | | Heavy smoker | 36 | | **Total** | | **529**| | **Total** | Nonsmoker | **716**| | | Occasional smoker | **65** | | | Regular smoker | **145**| | | Heavy smoker | **70** | | **Grand Total** | | **996**| #### Tasks Based on the Data **Question:** If one of the 996 people is randomly selected, find the probability of getting a regular or heavy smoker. - A) 0.146 - B) 0.216 - C) 0.095 - D) 0.442 **Solution Approach:** 1. Calculate the total number of regular and heavy smokers combined. - Regular smokers: 145 - Heavy smokers: 70 - Total regular or heavy smokers = 145 + 70 = 215 2. Calculate the probability: \[ P(\text{Regular or Heavy Smoker}) = \frac{\text{Number of Regular or Heavy Smokers}}{\text{Total Individuals}} = \frac{215}{996} \] 3. Simplify the fraction: \[ P = \frac{215}{996} \approx 0.216 \quad \text{(after rounding to three decimal places)} \] **Answer:** - The correct option is (B) 0.216. This table and solution help illustrate how to calculate
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