3) The power series for the sine function sin(x) is given by sin(x) = (-1)". -2--1 n=0 x²n+1 (2n + 1)! = X x³ x5 + 6 120 or all x. Use the first four terms in this series in the Horner evaluation function at a suitable value of x to give an approximation of sin(π/4).
3) The power series for the sine function sin(x) is given by sin(x) = (-1)". -2--1 n=0 x²n+1 (2n + 1)! = X x³ x5 + 6 120 or all x. Use the first four terms in this series in the Horner evaluation function at a suitable value of x to give an approximation of sin(π/4).
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
can you show me the code for this in python 3 , please provide explanations

Transcribed Image Text:(3) The power series for the sine function sin(x) is given by
x³
x 2n+1
(2n + 1)!
6
= 1.000001.
∞
X =
sin(x) = (-1)"
Σ(1)".
n=0
= X
Is this answer correct?
Briefly explain why, or why not.
+
for all x. Use the first four terms in this series in the Horner evaluation function at a suitable
value of x to give an approximation of sin(π/4).
Use your Horner's method function to evaluate the polynomial (x − 1)³ at the point
5
X
120
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