3) The masses m,= 4 kg and m, collision, the momentum of m/s. After the collision, the half of kinetic energy is lost. Find the velocities of the masses m, m, after the collision. (sin60=0.86 cos60–0.5) 2 kg move in the directions shown in Figure. Before the is equal to the momentum of m,, and m, has an initial velocity of 8 %3D m1 and vif m y 60 60 m,F-> x V1 8 m/s Before the collision
3) The masses m,= 4 kg and m, collision, the momentum of m/s. After the collision, the half of kinetic energy is lost. Find the velocities of the masses m, m, after the collision. (sin60=0.86 cos60–0.5) 2 kg move in the directions shown in Figure. Before the is equal to the momentum of m,, and m, has an initial velocity of 8 %3D m1 and vif m y 60 60 m,F-> x V1 8 m/s Before the collision
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3) The masses m,
4 kg and m,
2 kg move in the directions shown in Figure. Before the
has an initial velocity of 8
collision, the momentum of m, is equal to the momentum of m2,
m/s. After the collision, the half of kinetic energy is lost. Find the velocities of the masses m, and
, after the collision. (sin60=0.86 cos60-0.5)
and
m1
m2
vif
y
m1
y
60
60
m2
m
V2
'1 = 8 m/s
1112
Before the collision
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112 /A
19
17
8
6.
5
V/2
7
2
3
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