3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to

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Q: "For the logic circuit chown below FA F F=AB'+AB O E-A+B O F-AB F-A+B O

A: In this answer we will try to find the value of F as explained below.

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