3 The coordinates of P are (-3, 8) and the coordinates of Q are (9,-2). (b) Find the equation of the line parallel to PQ that passes through the point (6, -1). M₁ = 12 m = ½-½ x2x1 11-2-8 9-(-3) M=116 12 = M=-— (6,-1) -1 = (-₤X(6)+c 6=5-1 Y=-3x+4 y--동x+4 [3]
3 The coordinates of P are (-3, 8) and the coordinates of Q are (9,-2). (b) Find the equation of the line parallel to PQ that passes through the point (6, -1). M₁ = 12 m = ½-½ x2x1 11-2-8 9-(-3) M=116 12 = M=-— (6,-1) -1 = (-₤X(6)+c 6=5-1 Y=-3x+4 y--동x+4 [3]
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.4: Writing And Graphing Equations Of Lines
Problem 80E
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The coordinates of P are (-3, 8) and the coordinates of Q are (9,-2).
(b) Find the equation of the line parallel to PQ that passes through the point (6, -1).
M₁ = 12
m = ½-½
x2x1
11-2-8
9-(-3)
M=116
12
=
M=-— (6,-1)
-1 = (-₤X(6)+c
6=5-1
Y=-3x+4
y--동x+4
[3]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe68930b7-6552-46b3-ab6f-1ff15a13eb9f%2Fd3d35144-6bf7-485a-9a9d-e9f03dc28376%2Fuqcr5cb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3
The coordinates of P are (-3, 8) and the coordinates of Q are (9,-2).
(b) Find the equation of the line parallel to PQ that passes through the point (6, -1).
M₁ = 12
m = ½-½
x2x1
11-2-8
9-(-3)
M=116
12
=
M=-— (6,-1)
-1 = (-₤X(6)+c
6=5-1
Y=-3x+4
y--동x+4
[3]
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