3 Solve: (4x³ + 5x − 3) ÷ (x + 1)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem:**

Solve the polynomial division: 

\[ \frac{(4x^3 + 5x - 3)}{(x + 1)} \]

**Instructions:**

The problem requires you to perform a division of the cubic polynomial \(4x^3 + 5x - 3\) by the linear polynomial \(x + 1\). Use polynomial long division or synthetic division to find the quotient and remainder. 

**Guidance:**

1. **Identify the divisor and dividend**: 
   - Dividend: \(4x^3 + 5x - 3\)
   - Divisor: \(x + 1\)

2. **Perform Polynomial Long Division**:
   - Divide the first term of the dividend by the first term of the divisor. 
   - Multiply the entire divisor by this result and subtract from the dividend.
   - Repeat the process with the new polynomial formed after subtraction.

3. **Verify your result**:
   - Multiply the quotient by the divisor and add the remainder to ensure it matches the original dividend.

This solution approach will give insight into polynomial division, a key concept in algebra.
Transcribed Image Text:**Problem:** Solve the polynomial division: \[ \frac{(4x^3 + 5x - 3)}{(x + 1)} \] **Instructions:** The problem requires you to perform a division of the cubic polynomial \(4x^3 + 5x - 3\) by the linear polynomial \(x + 1\). Use polynomial long division or synthetic division to find the quotient and remainder. **Guidance:** 1. **Identify the divisor and dividend**: - Dividend: \(4x^3 + 5x - 3\) - Divisor: \(x + 1\) 2. **Perform Polynomial Long Division**: - Divide the first term of the dividend by the first term of the divisor. - Multiply the entire divisor by this result and subtract from the dividend. - Repeat the process with the new polynomial formed after subtraction. 3. **Verify your result**: - Multiply the quotient by the divisor and add the remainder to ensure it matches the original dividend. This solution approach will give insight into polynomial division, a key concept in algebra.
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