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3- Set up the following circuit for V = 5v. 11 12 R1 R2 9 с Measure and tabulate 1, 11, 12, Vde, Vrg, and Vab for the following conditions: a) R₁ = 1k, R₂ = 2 kn, b) R1 = 2k, R₂ = 1 kn, c) R₁ = 1k, R₂ = · 1 ΚΩ,

3- Set up the following circuit for V = 5v. 11 12 R1 R2 9 с Measure and tabulate 1, 11, 12, Vde, Vrg, and Vab for the following conditions: a) R₁ = 1k, R₂ = 2 kn, b) R1 = 2k, R₂ = 1 kn, c) R₁ = 1k, R₂ = · 1 ΚΩ,

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Electrical Circuit Analysis Exercise** **Objective:** Set up the following circuit for \( V = 5V \): **Circuit Diagram Description:** The circuit consists of a voltage source \( V \) connected to two parallel resistors \( R1 \) and \( R2 \). Specifically: - Points \( a \) and \( b \) are connected directly to the voltage source \( V \). - Resistor \( R1 \) is connected between points \( d \) and \( e \). - Resistor \( R2 \) is connected between points \( f \) and \( g \). The current \( I \) from the voltage source splits into two branches at point \( a \): 1. Current \( I1 \) flows through \( R1 \) from point \( d \) to \( e \) and then to point \( c \). 2. Current \( I2 \) flows through \( R2 \) from point \( f \) to \( g \) and then to point \( c \). After passing through the resistors, the current from both branches recombines at point \( c \) and then returns to the voltage source at point \( b \). **Task:** Measure and tabulate the total current \( I \), currents \( I1 \) and \( I2 \), and the voltages \( V_{de} \), \( V_{fg} \), and \( V_{ab} \) for the following conditions: 1. \( R1 = 1k\Omega \), \( R2 = 2k\Omega \) 2. \( R1 = 2k\Omega \), \( R2 = 1k\Omega \) 3. \( R1 = 1k\Omega \), \( R2 = 1k\Omega \) **Graph Explanation:** There is no graph included in this exercise. However, the circuit diagram illustrates the arrangement of resistors and the path of current through different branches of the circuit. By following these instructions and making the necessary measurements, students will gain a deeper understanding of electrical circuits, Ohm's Law, and the distribution of voltages and currents in parallel resistive networks.
Transcribed Image Text:**Electrical Circuit Analysis Exercise** **Objective:** Set up the following circuit for \( V = 5V \): **Circuit Diagram Description:** The circuit consists of a voltage source \( V \) connected to two parallel resistors \( R1 \) and \( R2 \). Specifically: - Points \( a \) and \( b \) are connected directly to the voltage source \( V \). - Resistor \( R1 \) is connected between points \( d \) and \( e \). - Resistor \( R2 \) is connected between points \( f \) and \( g \). The current \( I \) from the voltage source splits into two branches at point \( a \): 1. Current \( I1 \) flows through \( R1 \) from point \( d \) to \( e \) and then to point \( c \). 2. Current \( I2 \) flows through \( R2 \) from point \( f \) to \( g \) and then to point \( c \). After passing through the resistors, the current from both branches recombines at point \( c \) and then returns to the voltage source at point \( b \). **Task:** Measure and tabulate the total current \( I \), currents \( I1 \) and \( I2 \), and the voltages \( V_{de} \), \( V_{fg} \), and \( V_{ab} \) for the following conditions: 1. \( R1 = 1k\Omega \), \( R2 = 2k\Omega \) 2. \( R1 = 2k\Omega \), \( R2 = 1k\Omega \) 3. \( R1 = 1k\Omega \), \( R2 = 1k\Omega \) **Graph Explanation:** There is no graph included in this exercise. However, the circuit diagram illustrates the arrangement of resistors and the path of current through different branches of the circuit. By following these instructions and making the necessary measurements, students will gain a deeper understanding of electrical circuits, Ohm's Law, and the distribution of voltages and currents in parallel resistive networks.
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